# Torsten

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**Content Feed**

Function optimization meeting conditions

ht = rand(401,51); [n,m]=size(ht); I=@(h) sum(sum((ht-h).^2)); h0 = zeros(1,m); v1 = ones(m,1); w1 = -ones(m-1,1); A1 = di...

ongeveer 4 uur ago | 0

| accepted

define condition of the matrix

syms epsilon digits(100) A = [sym('1') sym('1')-epsilon;-sym('1') sym('1')+epsilon]; C1 = cond(A,1); C2 = cond(A,2); Cinf =...

ongeveer 9 uur ago | 1

I need a MATLAB simulation for the below second order differential equation

The example "Solve Second-Order BVP" under https://uk.mathworks.com/help/matlab/ref/bvp4c.html tells you exactly how to procee...

ongeveer 9 uur ago | 0

Solve Equation with symbolic Constants numerically.

syms w a b positive real u = a * w^3/(exp(b*w)-1); du = diff(u,w); wsol = solve(du==0,w)

ongeveer 10 uur ago | 0

| accepted

Problem writing a summation expression

Either you use "sum" or you make a loop over j. If you don't manage to get C_1, this is an indication that you should visit MAT...

1 dag ago | 0

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How to minimize the maximum error?

By a "linear approximating function" you mean a function l with l(x1,x2,x3) = a + b*x1 + c*x2 + d*x3 where a, b, c and d are ...

1 dag ago | 0

can someone help me regarding my code and error?

Adjust the sizes of the arrays involved in the calculation of "baseStationThroughputs" (see above). Further, use "fcn2optimexpr...

1 dag ago | 0

Problems related to initial and boundary conditions for solving PDE

This function sets adiabatic boundary conditions at both ends. function [pl,ql,pr,qr] = heatbc(xl,ul,xr,ur,t) pl = 0;%ul-293...

1 dag ago | 0

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Underdetermined Constrained Nonlinear System of Equations

My guess is that the x below is one of many other solutions. A = [1 1 1 1 1 1;-0.52 -0.52 0.3 0.3 0.64 0.64;0.94 -0.74 0.94 -0....

1 dag ago | 1

| accepted

How to set diffrent initial conditions as a vector.

I already showed you how to do that. If xvec and Tvec are your given vectors of grid points and associated temperatures, set ...

2 dagen ago | 1

| accepted

Runge-Kutta-4th-order solution of 3 ODEs

As you can see above, you get the same plot with a "professional" MATLAB solver (ODE45). So I guess there is something wrong wit...

3 dagen ago | 0

[Mass Transfer] How do I solve the following infinite series analytical solution to find time (t)? The answers in solution manuals show that the answer is 5085.85 seconds.

D = 1.5e-7; % Diffusivity R = 0.05; % Radius CA0 = 0.2; % Initial Conc. CAS = 0.0; CA_target = 0.1*CA0; % Target Conc. N = ...

3 dagen ago | 0

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Integral of user-defined function

Your function is not vectorized. Thus you have to use integral_value = integral(f, 0, Inf, 'ArrayValued',true) instead of int...

4 dagen ago | 1

| accepted

trying to create a plot of cost per mile when the trailer weight increases in a program I wrote and i cannot get it to work.

%for plot clear clc F='diesel';%input('gasoline or Diesel: ','s'); C=6;%input('number of engine cylinders '); T='yes';%inpu...

5 dagen ago | 0

Plotting the integral of a graph using cumtrapz.

Then my guess is that some of the x-values (maybe starting around 60) are NaN values. Remove them before applying "cumtrapz".

5 dagen ago | 2

Loop: for i = 1:L ;

because i got the task to do it like that and not to use: data(:,i+1) = data(:,i) * p. Then use for i = 2:L

5 dagen ago | 0

Accelerate a loop involving the built-in integral command

You will have to reorder the "Output" array, but I think the code should be faster. my_fun = @(t,param) t.^2; T = 2; omega = ...

6 dagen ago | 0

Why am i getting this error>>>Index exceeds the number of array elements (1). Error in Boom (line 38) Y(t) = X_best_so_far(t-1); % Use X_best_so_far value for the

As you correctly write in your code, the line X_best_so_far = X_best_so_far(1); % Initialize X_best_so_far as a scalar sets X_...

6 dagen ago | 0

Using Matlab to solve 1D Schrödinger Equation (Strange Eigenfunctions)

N = 2000; dy = 1/N; y = linspace(0,1,N+1).'; mL2V = @(y)1000*(y-0.5).^2; e = -1/(2*dy^2)*ones(N-1,1); d = 1/dy^2 + mL2V(y(2...

7 dagen ago | 1

| accepted

Numerically solve a 3rd order differential equation with 3 unknowns

Use "gradient" three times to get approximations for y', y'' and y''' in the points of your t-vector. Let diff_y, diff_y2, diff...

7 dagen ago | 0

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How to plot a continuous graph as shown in the below graph?

t1 = [1 6]; y1 = [1 1]; t2 = [6 7]; y2 = [0.45 0.45]; t3 = [7 8]; y3 = [1 1]; t4 = [8 9]; y4 = [0.4 0.4]; t5 = [9 11]; y5 = ...

7 dagen ago | 1

Storing parameters from a for loop in arrays

t = [0:0.2:3].'; y = [3.43101641262231;-0.527550212558249;3.43697613505530;0.186721377613475;5.11301585254667; 6.786264197...

8 dagen ago | 0

how can improve my code performanece, it uses a syms vector, i tried to delete y=t= sym(zeros(1, m + 3)); and it's faster but the solution of the function its wrong

You can't use t(k), t(k+1), t(k+2), y(k), y(k+1) and y(k+2) to define y(k). The values for these y's and t's are not yet known. ...

8 dagen ago | 0

error in for loop

I substituted 1/sqrt(x) by y in your equation. As you can see, there are only negative solutions such that resubstituting gives ...

8 dagen ago | 0

Why the nonlinear least square fitted curve is not a curve?

Why do you think the red line is not a curve ? For this point cloud of experimental data, I think the red line is the best you ...

8 dagen ago | 1

Sorting a matrix according to another one

A = [11 0.001 3 11 0.001 4 12 0.003 5 9 0.002 6 8 0.000 7 10 0.004 8 8 0.000 9 9 0...

8 dagen ago | 0

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Lower Dirichlet boundary condition for heat equation PDE

Your equations are not suited to be solved with pdepe. Both contain no second derivatives in space which is necessary for an eq...

8 dagen ago | 0

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plot between two variables

Use plot(1:365,[PR;ones(1,365)*PR_ave]); instead of plot(PR,PR_ave); if PR is a row vector, or plot((1:365).',[PR,ones(365...

8 dagen ago | 0

vpa solving 5 equations with 5 unknowns, but result is an empty structure

Did you read somewhere that "vpasolve" can handle inequalities ? Anyway, it seems the problem is too hard for a symbolic soluti...

9 dagen ago | 0

Second time derivative of ODE45 solution looks bumpy

t=[0 5]; initz=[0; 0]; [t,z]=ode15s(@f3, t, initz, odeset('RelTol',1e-12,'AbsTol',1e-12)); for i=1:numel(t) dz = f3(t(i),z...

9 dagen ago | 0

| accepted