Problem 74. Balanced number

Created by Cody Team

Solve Later

Given a positive integer find whether it is a balanced number. For a balanced number the sum of first half of digits is equal to the second half.

Examples:

 Input  n = 13722 
 Output tf is true

because 1 + 3 = 2 + 2.

 Input  n = 23567414 
 Output tf = true

All palindrome numbers are balanced.

This is partly from Project Euler, Problem 217.

Solve

Solution Stats

Last solution submitted on Sep 17, 2019

Last 200 Solutions

Problem Comments

2 Comments

2 Comments

GEORGIOS BEKAS on 25 Jan 2018

there is a problem with the test.
it does not accept the following code:
s1=[]
s2=[]
l=length(s)
if mod(l,2)~= 0
for i = 1:ceil(length(s)/2)-1
s1 = [s1,str2double(s(i))]
end
for i = ceil(length(s)/2)+1:l
s2=[s2,str2double(s(i))]
end
else
for i = 1:ceil(length(s)/2)
s1 = [s1,str2double(s(i))]
end
for i = ceil(length(s)/2)+1:l
s2=[s2,str2double(s(i))]
end
end

if sum(s1)==sum(s2)
tf = 1
else
tf = 0
end

Satadru Mukherjee on 25 Jun 2019

Simple code:

clc
clear all
close all
x=input('Enter the number');
Y=[];
c=0;
m=x;
while (m>0)
b=rem(m,10);
Y=[b Y];
c=c+1;
m=(m-b)/10;
end
r=c/2;
qw=floor(r);
if(qw==r)
t=0;
l=0;
for i=1:qw
t=t+Y(i);
end
for i=(qw+1):c
l=l+Y(i);
end
if(t==l)
disp('Yes');
else
disp('No');
end
else
t=0;
l=0;
for i=1:qw
t=t+Y(i);
end
for i=(qw+2):c
l=l+Y(i);
end
if(t==l)
disp('Yes');
else
disp('No');
end
end