How to sort points for plotting in MATLAB?
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Hello! I've got a little question about plotting points. In my project, I'm getting x and y coordinates and plotting them just when I read them from the socket, and I get something like this:

Just after plotting the coordinates I'm indexing them in two different vectors (one for x coordinates and the other for y coordinates). The problem is, when I try to plot them again in another script (or in another figure) the result is not what I expected.
The code I use for plotting the points the second time is:
figure()
for i=1:1000 %1000 is the length of x_vector and y_vector
plot(x_vector(i), y_vector(i), 'o')
hold on
axis([0 1920 0 1080]);
set(gca, 'ydir', 'reverse', 'xaxislocation', 'top')
end
And this is the result of the previous code:

I guess that the second time I try to plot the two vectors plot is trying to print some linear function through some regression instead of printing the cloud of points I expect.
Thank you
11 Comments
madhan ravi
on 23 Aug 2018
Edited: madhan ravi
on 23 Aug 2018
Upload your datas too (x_vector and y_vector).
Hi,
Why do you use a loop for this?
scatter(x_vector, y_vector, 'or')
axis([0 1920 0 1080]);
set(gca, 'ydir', 'reverse', 'xaxislocation', 'top')
dpb
on 23 Aug 2018
I think we would need to see how the x,y coordinates were stored and the original figure as well, not just the latter.
madhan ravi
on 23 Aug 2018
I second @dpb
Ángel González
on 23 Aug 2018
Ángel González
on 23 Aug 2018
Edited: Ángel González
on 23 Aug 2018
dpb
on 23 Aug 2018
x_vector = sort([x_vector x]);
y_vector = sort([y_vector y]);
And that explains it...you sorted the points independent of each other so the association of x,y is broken.
Ángel González
on 23 Aug 2018
Simply store the points as you receive them...you don't show code but
% preallocate
N=npts;
x_vector=zeros(npts,1);
y_vector=x_vector;
% collect, save...
for i=1:npts
% return x, y, here...
x_vector(i)=x;
y_vector(i)=y;
% do whatever else with x,y during download
...
end
presuming you know a priori how many points you're going to collect. If that is unknown, start with a big number and then remove those not needed.
Alternatively, while it's not efficient to code this way, the dynamic allocation as you wrote above is simple but overhead intensive--
x_vector=[]; y_vector=[];
while stilldownloading()
% get x, y
x_vector=[x_vector;x];
y_vector=[y_vector;y];
...
end
will keep each x,y pair together.
Jan
on 23 Aug 2018
Maybe replace
x_vector = sort([x_vector x]);
y_vector = sort([y_vector y]);
by
[x_vector, index] = sort([x_vector x]);
yTemp = [y_vector y];
y_vector = yTemp(index);
dpb
on 23 Aug 2018
That's calling sort repetitively every iteration...there's no indication of needing them sorted; if do, far more efficient to wait until done collecting and then sort the whole vector once.
Keeping and reordering y based on order of sorted x is, of course, necessry to keep the association between the two.
Alternatively, one could do slightly differently as
xy=[];
while collecting()
% get x, y
xy=[xy; [x y]];
...
end
xy=sortrows(xy);
and will have x,y in two columns in the one arrray sorted by increasing x
Accepted Answer
More Answers (1)
Afshin Aghayan
on 9 Oct 2019
0 votes
you can use this code for displaying any data in the form of [x, y, f(x,y)] or data with coordinate
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