how to solve log log equation??
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clc ,clear
syms m
m1=7;
m2=9.41;
t1=273+30;
t2=273+50;
t=40+273
b=(log10(log10(m1))-log10(log10(m2)))/((log10(t1)-(log10(t2))));
a=log10(log10(m1))-b*log10(t1);
a
b
log10(log10(m))=a-b*log10(t);
solve(m)
1 Comment
Matt J
on 23 Dec 2023
Why not as written?
Answers (1)
Here is the corrected code (note how the EQN is set up for the given equation):
clc, clearvars
syms m
m1=7;
m2=9.41;
t1=273+30;
t2=273+50;
t=40+273;
b=(log10(log10(m1))-log10(log10(m2)))/((log10(t1)-(log10(t2))));
a=log10(log10(m1))-b*log10(t1);
fprintf('a = %f; b = %f \n', [a, b])
EQN =log10(log10(m))==a-b*log10(t);
SOL = solve(EQN);
fprintf('Solution: m = %1.16f with solve() \n', double(SOL));
1 Comment
Or
m = 10^(10^(a-b*log10(t)))
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