Problem 6. Select every other element of a vector

Created by Cody Team

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Solution Stats

45022 Solutions
18905 Solvers

Last Solution submitted on Oct 21, 2020

Last 200 Solutions

Problem Comments

25 Comments

25 Comments

Show 22 older comments

Oleg Komarov on 26 Jan 2012

Not clear.

Giuseppe Cardillo on 1 Feb 2012

What does it mean? It is not clear

Hristo Alexiev on 1 Feb 2012

It's not understandable.

Aurelien Queffurust on 3 Feb 2012

This problem is definitely not clear.

Martin on 7 Feb 2012

Select the first, the third, the fifth, the seventh, ... element.

Sumit Agrawal on 30 Mar 2013

nice problem

kurguz on 6 Apr 2013

I cant understand this problem.

Maciej Kusper on 4 Jun 2013

nice

Jon on 13 Nov 2013

All solutions with score 10 or 11 use the regexp cheat.

L.K.R.Chaithanya kumar on 15 Jul 2014

very good one

Miguel Maya on 22 Feb 2015

I don't see why "x(1):2:length(x)" doesn't work, but "x(1:2:length(x))" does if it's the same thing?
It worked for me in MATLAB

Armando Femat on 3 Dec 2015

Yes, you should change the redaction of the problem,maybe

Mir Rejaul Karim on 16 Jul 2016

function y = everyOther(x)
for i=1:length(x)
if mod(x(i),2)~=0
y(i)=x(i)
end
end
y=y(y>0)

end

What's wrong with this solution?

Rong Zeng on 21 Aug 2016

y = x(mod(x,2)==1);
it's not working, and i cant see why

Vineet Kumar on 25 Aug 2016

nice problem

Jun Ren Tan on 26 Dec 2016

y = x(1:2:length(x));?

SIVAPRAKASH DANABALASINGAM on 10 Jan 2017

nice

Taha MRIHEEL on 3 Apr 2017

good

Nikoo Azarm on 6 Apr 2017

I can't understand, why is this wrong?
j=1;
for i=1:length(x)
if rem(x(i),2)~=0
y(j)=x(i);
j=j+1;
end
end

Barrie Cooper on 25 Apr 2017

Nice problem, but I have been doing this with my son and it would be good if the exercises were more gently graduated with relevant syntax so he can learn without relying on his dad knowing Matlab!

James Tanner on 26 Jun 2017

I can't believe someone solved this with size 9.

Gulen Insay on 2 Sep 2017

The leading solution is not a solution. It just makes all the test assertions true.

Ghetto blaster on 22 Oct 2018

Indexing is one of more important things in matlab and matrices. Gotta learn them good before heading on.

Banana on 25 Sep 2019

Helo, hey hey ey

Matlab Expert on 7 Mar 2020

Indexing is one of more important things in matlab and matrices. Gotta learn them good before heading on.

Solution Comments

Solution 3107341

1 Comment

1 Comment

Marco Torres on 7 Oct 2020 at 22:45

LOL, the solution is in the Test Suite :)

Solution 3094316

1 Comment

1 Comment

天夏 on 7 Oct 2020 at 2:12

why wrong?
My program woks!

Solution 3069898

1 Comment

1 Comment

akarsh saxena on 5 Oct 2020 at 16:12

error in template

Solution 3034759

1 Comment

1 Comment

Tatjana Dulinskiene on 2 Oct 2020 at 15:54

easy

Solution 2586085

1 Comment

1 Comment

Piero Cimule on 19 Jun 2020

y = x(1:2:length(x))

Solution 2289691

1 Comment

1 Comment

swagata laxmi sengupta on 17 May 2020

this was so easy

Solution 2175863

1 Comment

1 Comment

Lewis Wootton on 26 Mar 2020

why is it we cant just see a correct answer once we've submitted enough wrong answers? That would actually improve learning time as opposed to going round in circles not knowing what to do.

Solution 2126234