The function 'F', defined as:
,will always return an integer if the input is a natural number (in radians). Furthermore, since the cosine and sine of 0, are 1 and 0 respectively, therefore F(0) = 0. For a given natural number 'n' your task is to find the value of F(n).
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Can someone please explain test case 4? I don't see what is going on, as intmax-4 is clearly not 1234567891011.
I could only pass this case by bodging x inside the function, which is clearly unsatisfactory.
intmax - 4 is not equal to 1234567891011. But
F(intmax-4) is equal to F(1234567891011). The given function can have same output for different inputs.
Hi Mark,
Trigonometric functions are naturally periodic. So we can expect same function return from different inputs.