Problem 470. Scoring for oriented dominoes
Given a list of ordered pairs, and the order they should be placed in a line, find the sum of the absolute values of the differences.
list = [1 2 5 3 2 4
order = [1 3 2]
yields: [1 2][2 4][5 3] or: abs(2-2) + abs(4-5) or: 0 + 1 or: 1
Solution Stats
Problem Comments
-
3 Comments
Is Test #3 correct? When I solve it with pencil and paper, I get 15 instead of 14.
[5 4][1 2][2 4][7 5][4 8][4 5][1 6]
= -3 + 0 + 3 + -1 + -4 + -4
= 3+0+3+1+4+4
=15
Have I missed something?
No it's 14. With the ordering, you should get:
[5 4][1 2][2 4][4 8][1 6][4 5][7 5], and the sum is abs(4-1) + abs(2-2) + abs(4-4) + abs(8-1) + abs(6-4) + abs(5-7) = 3 + 0 + 0 + 7 + 2 + 2 = 14
good
Solution Comments
Show commentsProblem Recent Solvers831
Suggested Problems
-
Return a list sorted by number of occurrences
2673 Solvers
-
1706 Solvers
-
Getting the indices from a matrix
625 Solvers
-
313 Solvers
-
Flip the vector from right to left
8467 Solvers
More from this Author51
Problem Tags
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!