Problem 46716. Matrix with increasing numbers (★★★★)

Created by Anirban Pal

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Create a matrix Z with m rows and n columns that contain the numbers 1 to m*n in ascending order in the following manner. The first row will contain numbers 1 to n. The second row will contain n+1 to 2n and so on. Thus, if m = 3, n = 4, the output matrix Z will have 3 rows and 4 columns and will be the following:
[1 2 3 4;
5 6 7 8;
9 10 11 12]
This become trivial if you use loops, but do this without using loops, i.e. for/while not permitted. Additionally, the reshape command makes this very easy, so avoid that as well.

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Last Solution submitted on Jul 16, 2024

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goc3 on 15 Apr 2023

Fortunately, there is an abbreviation that can be used that will not be triggered by searches for "for": arrayfun(..., "Uni", 0). Incidentally, "Un" (or "un") can also be used while 0 is equivalent to false in this context. These abbreviations also work for cellfun.

Dyuman Joshi on 15 Apr 2023

Technically, arrayfun (cellfun as well) is just a loop in disguise. All in all, OP is asking for a vectorized solution.

Christian Schröder on 16 Apr 2023

@Dyuman You're right of course, but technically the problem description also says "do this without using loops, i.e. for/while not permitted", so arrayfun, cellfun and all the other kinds of fun that you can have with MATLAB are permitted. :)

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Problem 46716. Matrix with increasing numbers (★★★★)

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Problem 46716. Matrix with increasing numbers (★★★★)

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Last 200 Solutions

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