Given a logical vector v, and a positive integer n, return the smallest index i that satisfies:
all( v(i : i+n-1) ) == true
For Example,
v = logical([0, 1, 1, 0, 0, 1, 1, 1, 1, 1, 0]); i = consecutiveFind(v, 4);
Then:
i = 6
If there is no sequence of n consecutive true, then i should be an empty array.
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The test suite is not enough because it does not contain any case that the number of consecutive true bits is exactly same as n.