Given a matrix, find the average of the second largest values in each row. The same value does not exist on a row.
Example: input x = [1 2 3 4;8 7 6 5;9 0 1 4] >>> output y = (3+7+4) / 3
the following 4 lines solve this question
[max1,ind1]=max(x,[],2)
x(sub2ind(size(x),[1:3],ind1'))=NaN
[max2,ind2]=max(x,[],2)
y=mean(x(sub2ind(size(x),[1:3],ind2')))
yet the online checker returns not a valid answer
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Solution 1448126
this
x2=x
[max1,ind1]=max(x2,[],2)
x2(sub2ind(size(x),[1:3],ind1'))=NaN
[max2,ind2]=max(x2,[],2)
y=mean(x2(sub2ind(size(x),[1:size(x,1)],ind2')))
solves the question yet the checker returns not a valid answer.