Problem 362. Find matching string from a list of strings

Solution 1900989

Submitted on 15 Aug 2019 by Nikolaos Nikolaou

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Test	Status	Code Input and Output
1	Pass	inStr = 'ball'; strList = {'ball', 'bell', 'barn'}; assert(isequal(findMatch(inStr, strList), 'ball')); q = 1×3 logical array 1 0 0 k = 1 0 0 outStr = 'ball'
2	Pass	inStr = 'auG'; strList = {'May', 'June', 'July', 'August', 'September'}; assert(isequal(findMatch(inStr, strList), 'August')); q = 1×5 logical array 0 0 0 1 0 k = 0 0 0 0 0 outStr = 'August'
3	Pass	inStr = 'Ju'; strList = {'May', 'June', 'July', 'August', 'September'}; assert(isequal(findMatch(inStr, strList), '')); q = 1×5 logical array 0 1 1 0 0 k = 0 0 0 0 0 outStr = 0×0 empty char array
4	Pass	inStr = 'fontn'; strList = {'FontName', 'FontUnits', 'FontSize', 'FontWeight'}; assert(isequal(findMatch(inStr, strList), 'FontName')); q = 1×4 logical array 1 0 0 0 k = 0 0 0 0 outStr = 'FontName'
5	Pass	inStr = 'weight'; strList = {'FontName', 'FontUnits', 'FontSize', 'FontWeight'}; assert(isequal(findMatch(inStr, strList), 'FontWeight')); q = 1×4 logical array 0 0 0 1 k = 0 0 0 0 outStr = 'FontWeight'
6	Pass	inStr = 'ball'; strList = {'baseball', 'balloon', 'ball'}; assert(isequal(findMatch(inStr, strList), 'ball')); q = 1×3 logical array 1 1 1 k = 0 0 1 outStr = 'ball'
7	Pass	inStr = 'bal'; strList = {'baseball', 'balloon', 'ball'}; assert(isequal(findMatch(inStr, strList), '')); q = 1×3 logical array 1 1 1 k = 0 0 0 outStr = 0×0 empty char array