Problem 2592. LocateMembership | Membership of Matrix in another matrix

Created by Vishal

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{"relationships":[{"relationshipType":"http://schemas.mathworks.com/matlab/code/2013/relationships/document","targetMode":"","relationshipId":"rId1","target":"/matlab/document.xml"},{"relationshipType":"http://schemas.mathworks.com/matlab/code/2013/relationships/output","targetMode":"","relationshipId":"rId2","target":"/matlab/output.xml"}],"parts":[{"partUri":"/matlab/document.xml","relationship":[],"contentType":"application/vnd.mathworks.matlab.code.document+xml","content":"<?xml version=\"1.0\" encoding=\"UTF-8\"?>\n<w:document xmlns:w=\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\"><w:body><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>Let a and b be given by</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"code\"/></w:pPr><w:r><w:t><![CDATA[ a = [ 2 1 1 1   \n       1 2 1 1 \n       1 1 2 1 \n       1 1 1 2\n       4 0 0 0 ] \n\n b = [ 2 1 1\n       1 2 1\n       1 1 2 ]]]></w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>then b can be created using a (b is wholly present in a). So output should be location of central element of b in a.</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>Here output is [3,3] else it should be [0,0].</w:t></w:r></w:p></w:body></w:document>"},{"partUri":"/matlab/output.xml","contentType":"text/xml","content":"<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"no\" ?><embeddedOutputs><metaData><evaluationState>manual</evaluationState><layoutState>code</layoutState><outputStatus>ready</outputStatus></metaData><outputArray type=\"array\"/><regionArray type=\"array\"/></embeddedOutputs>"}]}

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Last Solution submitted on Feb 07, 2023

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rifat on 16 Sep 2014

in test case 3, b is not available in a. I might be wrong.. Please Check

Jean-Marie Sainthillier on 16 Sep 2014

Not logic to ask a scalar (if no location), an array (if 1), and a cell (if 2). And why not add the example (difficult) in the tests ?

Vishal on 17 Sep 2014

@rifat : updated, thanks for info

Jan Orwat on 18 Sep 2014

Nice problem. Some solutions (using conv, filter2 etc.) doesn't check conditions properly. Adding a=2*ones(4); b=3*eye(3)+1; or a=0; b=0; or similar can improve the testsuite;

Jean-Marie Sainthillier on 18 Sep 2014

The solution in the example is [2 2;3 3].

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Problem 2592. LocateMembership | Membership of Matrix in another matrix

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Problem 2592. LocateMembership | Membership of Matrix in another matrix

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