Problem 2397. Leap Year
According to Gregorian Calender(which is in use now, in many countries),decide whether a given year is a leap year or not. Give 'true' if the given year is a leap year and 'false',if not.
Note: In the Gregorian calendar 3 criteria must be taken into account to identify leap years:
The year is evenly divisible by 4; If the year can be evenly divided by 100, it is NOT a leap year, unless; The year is also evenly divisible by 400. Then it is a leap year.
Solution Stats
Problem Comments
-
3 Comments
Kumar, in problem #4 there is one to many right parenthesis. George...
Actually I just realized it is the "isequal" is missing in test #4.
Thanks George.Am extremely sorry for that.I just corrected it.
Solution Comments
Show commentsProblem Recent Solvers104
Suggested Problems
-
Return elements unique to either input
773 Solvers
-
Check if number exists in vector
12087 Solvers
-
Split a string into chunks of specified length
1864 Solvers
-
Create a Multiplication table matrix...
552 Solvers
-
410 Solvers
More from this Author1
Problem Tags
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!