Case #3 is not symmetric...please check.
I fixed the wording.
Why the vector from "Test Suite" "Test 3" is symmetric?
x = [-1 0 0 1];
y_correct = 1; %% WHY 1?
I updated test case #3.
just a quick hint for this test: at the moment, one can pass this test simply checking whether x(1)==x(end).
However, to me at least, it makes more sense to split the check for even and odd vectors and to check if the corresponding symmetrical elements are the same or not.
If any of the pairs of elements are not equal, then we exit the cycle and we terminate with a false/0.
This is the way I figured out a robust check, otherwise it's just cheating.
Include a test case where first and last are same, but ones in middle aren't (say [1 2 4 3 5 2 1])
I need to learn more.
What if you update the test #3 in test suite?
Find the sum of the elements in the "second" diagonal
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Generate a NaN...on purpose
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Remove entire row and column in the matrix containing the input values
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Duplicate a character
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