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How to get quotient value after division without round off?

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I want to get quotient (only integer value) after division of two numbers without rounding off.
n1 = I1(i,j) +1;
for k1= 0:7
l1(8-k1) = rem(n1,2);
n1 = fix(n1/2);
end
when n1 = 157 in first line :
then in fourth line after dividing by 2 , n1 is taking 79 (157/2 = 78.5) value
but i want n1 to take 78 value.
  2 Comments
dpb
dpb on 19 Jun 2021
>> n1=157;
>> fix(n1/2)
ans =
78
>>
You've done something else you've not told us about first...like an intermediate store with a rounding operation, maybe.
Even in your code;
>> n1=157;for k1= 0:7
l1(8-k1) = rem(n1,2);
n1 = fix(n1/2)
end
n1 =
78
n1 =
39
n1 =
19
n1 =
9
n1 =
4
n1 =
2
n1 =
1
n1 =
0
>>

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Accepted Answer

Mouhamed Niasse
Mouhamed Niasse on 19 Jun 2021
Hello,
I tried to execute your portion of code but, just as expected, n1 has the value 78 not 79 for me.
Try using the function 'floor' instead of 'fix', they normally give the same output for positive input values.
  1 Comment
Khushboo Singla
Khushboo Singla on 19 Jun 2021
Thankyou so much. Though same problem persisted in my code BUT i got another solution
as I subtracted remainder(from third line) from the number(n1) everytime so that it will give only interger value after division as shown:
n = 157;
for k1= 0:7
l1(8-k1) = rem(n1,2);
n1 = fix((n1-l1(8-k1))/2)
end

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More Answers (1)

Steven Lord
Steven Lord on 19 Jun 2021
If one or both of the numbers are stored as an integer type you could use the idivide function.
idivide(int16(157),2)
ans = int16 78

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