How to split vector to columns based on index?
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Hi all
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/530314/image.png)
Hi all
How do I split this vector in such a way that everytime the consecutive value is less than the one before the vector would split into different columns based on that index. I've tried writing this code to get the index of where the change happens but it doesnt work and I don't know how to split the vector into different columns.
for k=1:length(SOC2_stop)
if SOC2_stop(k+1)<SOC2_stop(k)
index(k)=k;
end
end
1 Comment
Bob Thompson
on 24 Feb 2021
index = (find(SOC2_stop(2:end)-SOC2_stop(1:end-1)<0))+1;
As for the splitting into new columns others probably have much fancier ways to accomplish that than I would, but if you want it all in one matrix then you're going to need to identify the maximum number of elements to fit in one column first.
nrows = max(index(2:end)-index(1:end-1));
newarray = nan(nrows,numel(index)+1);
Answers (1)
KALYAN ACHARJYA
on 24 Feb 2021
Edited: KALYAN ACHARJYA
on 24 Feb 2021
diff_data=diff(column_data);
idx=find(diff_data<0)
idx gives the indices of raspective array elements, where present value is greater than next one. Afterwards, use the mat2cell function to segemnt the array in different cell array elements (Cell array is useful to save multiple arrays with different sizes).
2 Comments
KALYAN ACHARJYA
on 24 Feb 2021
Please see the mat2cell function in MATLAB Doc (Do Google)
Other Way using loop (Not so efficient)
result=cell(1,length(idx))
for i=1:length(idx)-1
result{i}=data(idx(i):idx(i+1)-1);
end
result{end}=data(idx(end):length(data));
result
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