plot discrete time domain signals
8 views (last 30 days)
Show older comments
Jinquan Li
on 14 Feb 2021
Commented: Paul Hoffrichter
on 15 Feb 2021
Given n=[-1:0.01:10]. Plot the discrete time domain signal: y[n]=e^(-n)*u(n).
Below is my program but i'm not sure if it's correct since this is my fisrt time learning Matlab. Please help. Thanks!
n=-1:0.01:10;
y=exp(-n).*heaviside(n);
stem(t,y)

1 Comment
Paul
on 14 Feb 2021
Edited: Paul
on 15 Feb 2021
Be careful using heaviside for u[n]. In control systems and signal processing the function u[n] is the unit step function that is (typically) defined as
u[n] = 1 for n >= 0
u[n] = 0 for n < 0.
However, the default defintion of the heaviside function in Matlab has heaviside(0) = 0.5., which is clearly seen in the plot. Is that the desired answer?
Also, it looks a bit peculiar to have non-integer values of n. Please make sure that's the correct problem statement.
Accepted Answer
Paul Hoffrichter
on 14 Feb 2021
I recommend using following substitutions:
plot(t,y)
axis( [-1 10 0 1])
6 Comments
Paul Hoffrichter
on 15 Feb 2021
Take a look at
The following defines the myStep function so that myStep(0) is 0 instead of 0.5.
myStep = @(n) (n>0);
If you wanted a value of 1 at n = 0, then you could use this instead:
myStep1 = @(n) (n>=0);
More Answers (0)
See Also
Categories
Find more on Annotations in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!