Trouble is... if you've not spotted... y is the value entered in the function (at the top of the question). So if y in the poly_input(y) is blank, then the message appears!
How do I get my code to recognise an empty function input?
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function P = poly_input(y)
while
if isempty(y) == 1
y = input('Invalid, no value entered. Enter a value: ', 's');
end
end
end
Basically, i'd like for a re-entry of number message to appear if no value is entered for y!
Please and thanks!
4 Comments
Image Analyst
on 7 Apr 2013
Edited: Image Analyst
on 7 Apr 2013
See my comment about how to handle nargin (number of input arguments) being zero.
Answers (3)
Wayne King
on 7 Apr 2013
isempty() should work
y = input('What is your favorite color? ','s');
if isempty(y)
y = input('Invalid, no value entered. Enter a value: ', 's');
end
0 Comments
Image Analyst
on 7 Apr 2013
Try this:
while true
% Ask user for a number.
defaultValue = 45;
titleBar = 'Enter a value';
userPrompt = 'Enter the number ';
caUserInput = inputdlg(userPrompt, titleBar, 1, {num2str(defaultValue)});
if isempty(caUserInput) % Doesn't work. Not empty if user input is null.
return;
end; % Bail out if they clicked Cancel.
numericalValue = str2double(cell2mat(caUserInput));
% Check for a valid integer.
if isnan(numericalValue)
% They didn't enter a number.
% They clicked Cancel, didn't enter anything
% or entered a character, symbols, or something else not allowed.
message = sprintf('I said it had to be a number.\nTry again.');
uiwait(warndlg(message));
else
break;
end
end
3 Comments
Matt Butts
on 19 May 2016
If I'm not mistaken, this will also require a modification to the function definition:
function P = poly_input(varargin)
if nargin < 1
y = input('Invalid, no value entered. Enter a value: ', 's');
else
y = varargin{1};
end
Steven Lord
on 19 May 2016
Nope. This works just fine. [Whether it's preferred or not is a different question. Personally I'd probably have poly_input use narginchk to throw an error if you didn't call it with 1 input.]
function P = poly_input(y)
if nargin < 1
y = input('Enter a value for y: ');
end
P = [y 0];
Call it like this and you will be prompted to enter a value.
P = poly_input()
Garret Mans
on 23 May 2019
I know I'm only a few years late to this thread, but I'm confused why this question got so overcomplicated.
You just need the input and an initial while loop to catch the empty input. Maybe theres something I'm missing but as far as the question asked, this solves the problem just fine:
function gimmiStuff(y)
while isempty(y)
y = input('You gave me empty stuff. Gimmi stuff: ');
end
% Continue with function
.
.
.
end
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