why do I get different EigenVectors than my instructor got?

[Roberto Vieytes]

The eigenvector Matlab give us are normaliced, your intructor don use normalices vectors. bye

Answer 1

[Steven Lord]

If v is an eigenvector of A corresponding to eigenvalue d, multiplying v by a non-zero scalar k results in another eigenvector of A with the same eigenvalue. In this case, the first column of V matches the eigenvector [2; 1] and the second matches [10; 7].

>> A = [0.6 0.5; -0.175 1.2];
>> [V, D] = eig(A);

>> k1 = 1./max(V(:, 1))
k1 =
         -2.23606797749979

>> k1*V(:, 1)
ans =
                         2
                         1

>> k2 = 10./V(1, 2)
k2 =
         -12.2065556157337

>> k2*V(:, 2)
ans =
                        10
                         7

[zolteckx6]

% I really appreciate your time on this one!
A = [1 2 ; 5 4]
[V, D] = eig(A)
k1 = 1./max(V(:, 1))
k1*V(:, 1)
k2 = 10./V(1, 2)
W = k2*V(:, 2)
V2 = W/5
% a question of understanding
% doing the problem by hand naturally leads to V1 = [-1 1]
% and V2 = [2 5]
% plugging in -6 for labda gives (-5 2 ; 5 -2)
%  I understand that [-985/1393 985/1393] = [-1 1]
% but why does matlab give me these values?

[zolteckx6]

^ This is NOT the same matrix