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How to pick the values from individual grids ?

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aa
aa on 25 Sep 2020
Commented: Turlough Hughes on 29 Sep 2020
Hi everyone,
May someone help me here ,,
My data set is consists of three paramateres ... x, y and z ..
the x, y paramteres are grided at an interval of 0.005, This give me a matrix of 16 by 16 grid ..
In each grid z-values are placed. Now I want to calculate the the z vales in each grid ...
The figure show the pictorial representation of data in each grid ... My task is to generate an output file with 256 columns and each colum give us the values of point placed in each grid ..
Thank you
clear all
%clc
a=xlsread('data');
x=a(:,1);% x parameter
y=a(:,2); %y parameter
z=a(:,3); % z parameter
%Grid scale
x2=-130.04:0.005:-129.96;
y2=45.91:0.005:45.99;
  8 Comments
aa
aa on 25 Sep 2020
Yes ,,, with a Nan for empity cells.

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Accepted Answer

Turlough Hughes
Turlough Hughes on 25 Sep 2020
Edited: Turlough Hughes on 29 Sep 2020
The objective is to create an excel sheet with columns of data having different length. You can store data that has different lengths in a cell array as mentioned in the comments by inserting following line into the answer provided by KSSV after idx has been determined in the inner loop:
zStore{1,j+(n-1)*(i-1)} = z(idx); % inside the loop
To demo the problem one can alternatively generate an example of zStore with the following:
for c = 1:256
N = randi([50 200],1);
zStore{1,c} = rand(N,1);
end
Convert zStore to a matrix padded with NaNs so that all columns have the same length as the longest column vector in zStore:
N = max(cellfun(@numel,zStore));
zMat = nan(N,256);
for i = 1:numel(zStore)
zMat(1:numel(zStore{1,i}),i) = zStore{1,i};
end
Then you can write the matrix out to an excel sheet
writematrix(zMat,'data.xlsx')
  2 Comments
Turlough Hughes
Turlough Hughes on 29 Sep 2020
I've edited the line that goes inside the loop to store z values. Let me know if that works for you.

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