# How can I create n arrays of size 100 each with random integer values?

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Rami Kanj on 13 Dec 2019
Answered: Steven Lord on 13 Dec 2019
c = cell(1,100)
for i = 1:100
c{i} = randi(100)
end
I tried doing this but it only gives 100 arrays of size 1.
I need 1-D arrays
Any other solution is gladly welcomed.
Thank you!

Alex Mcaulley on 13 Dec 2019
c = cell(1,100)
for i = 1:100
c{i} = randi(100,1,100)
end

Rami Kanj on 13 Dec 2019
Not quite I need 100 1D arrays each containing 100 elements.
Without cell it is a hassle but I think a way around this without using cell is to create 1 big 1D array which contains 10,000 elements and take 100 elements each time and place it into an array and add an offset to take the next 100 elements until it ends.
Alex Mcaulley on 13 Dec 2019
It is simpler with @Guillaume suggestion, creating 100x100 matrix and then, each row (or each column) is an array of 100 elements:
result = randi(50, 100)
result(1,:) %1x100 array
Rami Kanj on 13 Dec 2019
Okay Thank you!!

Bhaskar R on 13 Dec 2019
c = cell(1,100);
for i = 1:100
c{i} = randperm(100);
end

Steven Lord on 13 Dec 2019
Since all of your arrays are the same size, I would consider stacking them in one of the dimensions in which they have size 1.
A = randi([-10 10], 5, 8);
In this example A contains 5 "arrays" (the rows) of random integer values between -10 and 10, each "array" having size [1 8]. To use the third "array":
third = A(3, :)
For 2-dimensional arrays, you could stack them in the third dimension like pages in a book.
B = randi([-10 10], 3, 3, 7);
fifth = B(:, :, 5)