Avoiding many if-Statetments in a for-loop
3 views (last 30 days)
Show older comments
Hello everyone :)
I would like to run a for-loop over a vector. What to do with each element in the vector depends on many if-else statements. I simplified it like this:
clear variables;
rng default;
V1 = rand(365,1);
V2 = rand(365,1);
V2 = V2 <= 0.5;
V3 = rand(365,1);
V3 = V3 <= 0.3;
Vresult = zeros(length(V1),1);
tstart = 1;
tend = length(V1);
for t = tstart:tend
if V2(t) == 1
if V3(t) == 1
Vresult(t) = do_stuff(V1(t));
else
Vresult(t) = do_different_stuff(V1(t));
end
else
if V3(t) == 1
Vresult(t) = do_even_different_stuff(V1(t));
else
Vresult(t) = do_even_more_different_stuff(V1(t))
end
end
end
function [var_out] = do_stuff(var_in)
var_out = var_in * 5;
end
function [var_out] = do_different_stuff(var_in)
var_out = var_in + 3;
end
function [var_out] = do_even_different_stuff(var_in)
var_out = var_in / 4;
end
function [var_out] = do_even_more_different_stuff(var_in)
var_out = var_in - 2;
end
With even more if-else conditions and more calculations per statement it gets really confusing and unreadable. And I feel like I'm writing the same code over and over again as only some parts of the code are different in each statement and other parts stay the same.
How can I make my code more efficient, easier to read and maintainable? Sorry if this should be common knowledge :D
Accepted Answer
Adam Danz
on 11 Dec 2019
I'm assuming the local functions provided are just demo functions. If those functions can be vectorized, it's very likely that you don't need a loop or any conditional statements at all.
Here's a method of performing a function on each element of vector V1 based on the values of V2(n) and V3(n) which are both logical vectors. It uses a switch-case instead of a series of conditional statements. The switch expression must be a scalar or char vector which is why I'm converting the logical values to char where 1 is true and 0 is false.
VAll = [V2,V3];
for t = tstart:tend
switch sprintf('%d %d',VAll(t,:))
case '1 1'
Vresult(t) = do_stuff(V1(t));
case '1 0'
Vresult(t) = do_different_stuff(V1(t));
case '0 1'
Vresult(t) = do_even_different_stuff(V1(t));
case '0 0'
Vresult(t) = do_even_more_different_stuff(V1(t));
otherwise
% This should never happen unless VAll is unexpected
error('Something is unexpected about the internal variable ''VAll''.')
end
end
2 Comments
Steven Lord
on 11 Dec 2019
Rather than turning your cases into char vectors I'd probably turn them into numbers. If V2 and V3 can only take on values 0 and 1, treat them like bits in a binary number.
% You may want to assert here to guard against V2 and V3
% taking values other than 0 or 1
VAll = [V2, V3];
v = polyval(VAll, 2);
switch v
case 0 % V2 = 0, V3 = 0
case 1 % V2 = 0, V3 = 1
case 2 % V2 = 1, V3 = 0
otherwise % V2 = 1, V3 = 1
end
Otherwise treat them like digits in an N-ary number.
Adam Danz
on 11 Dec 2019
Edited: Adam Danz
on 11 Dec 2019
I like the idea of using numbers rather than char vectors (clever use of polyval!). VAll is an nx2 logical matrix so the switch would need to be
VAll = [V2, V3];
for t = tstart:tend
switch polyval(VAll(t,:),2)
case 0 % V2 = 0, V3 = 0
case 1 % V2 = 0, V3 = 1
case 2 % V2 = 1, V3 = 0
otherwise % V2 = 1, V3 = 1
end
end
More Answers (1)
Adam
on 11 Dec 2019
Edited: Adam
on 11 Dec 2019
Something like this would seem to do the job, off the top of my head, though I may be over-simplifying it...
case1 = V2 && V3;
case2 = V2 && ~V3;
case3 = ~V2 && V3;
case4 = ~V2 && ~V3;
Vresult( case1 ) = do_stuff( V1( case1 ) );
Vresult( case2 ) = do_different_stuff( V1( case2 ) );
Vresult( case3 ) = do_even_different_stuff( V1( case3 ) );
Vresult( case4 ) = do_even_more_different_stuff( V1( case4 ) );
0 Comments
See Also
Categories
Find more on Performance and Memory in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!