char time: wrong label on years

Hello,

I converted time from Gregorian days to classical label in dd/mm/yy in this way:

time_1= ncread ('/path/.nc', 'date_time');

time1=datestr(time_1,0);

but the label on YEARS is wrong, as you can see in the image. I have 0014, don't 2014!

Could you help me to have the right year?

thanks

example:

Answer 1

[dpb]

The problem is the explicit four-digit string for the year -- that overrides any pivot year input for either datenum/datestr as well as the recommended datetime.

You'll have to either fix up the input string or I'd recommend something like--

>> dtm=datetime('24-May-0014')
dtm = 
  datetime
   24-May-0014
>> datetime(datevec(dtm)+[2000 0 0 0 0 0])
ans = 
  datetime
   24-May-2014 00:00:00
>> 

to fix up the year.

[Steven Lord]

There's no need to convert back from a datetime to a datevec and back to a datetime just to add 2000 calendar years.

dt = datetime('24-May-0014')
dt2 = dt + calyears(2000)

[dpb]

I wondered about that...apparently I did something wrong or just never did get around to try the addition of a duration, Steven.

Thanks for pointing it out...

[Steven Lord]

There are a few situations where a duration and a calendarDuration are slightly different.

dt = datetime('3-Mar-1999')
dt1 = dt + years(1) % March 2nd 2000 5:49:12
dt2 = dt + calyears(1) % March 3rd 2000

years(1) is 365.2425 days. calyears(1) is exactly one calendar year, taking into account leap days.

[dpb]

Ah, yes. I knew something made me react to use the integer via datevec even though I didn't have a conscious connection to what, precisely. calyears() never came to mind; not yet totally assimilated the new(ish) datetime class and friends...

Answer 2

[Sofia Stella]

At least I've solved in this way:

time0 = datenum(1970,1,1,0,0,0);

timeTOT = time+time0;

thank you all!