how to write a function for quadratic equation

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I wrote this into matlab but it doesn't work, can someone explain why?
function [x1,x2] = QuadraticEquation (a,b,c)
d=b^2-4*a*c;
if d>=0
disp ('two roots exist')
x1=(-b-sqrt(d))/2*a
x2=(-b+sqrt(d))/2*a
plot(x1,0,'rx',x2,0,'rx')
hold on
x=-10:10
y=a*x.^2+b*x+c
plot(x,y)
hold off
else
disp ('no real roots’)
end
  3 Comments
Alisha Mistry
Alisha Mistry on 7 Dec 2019
It keeps saying the variables a,b,c aren't defined but i put them into a script as a function so why does it still say that message?
Image Analyst
Image Analyst on 7 Dec 2019
You need to pass in something. You can't just click the green Run triangle on the toolbar. See Matt J's Answer below.

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Accepted Answer

Matt J
Matt J on 7 Dec 2019
Edited: Matt J on 7 Dec 2019
[x1,x2] = QuadraticEquation (1,-2,0)
function [x1,x2] = QuadraticEquation (a,b,c)
d=b^2-4*a*c;
if d>=0
disp ('real roots exist')
x1=(-b-sqrt(d))/(2*a); %<---------- brackets in denominator
x2=(-b+sqrt(d))/(2*a); %<---------- brackets in denominator
plot(x1,0,'rx',x2,0,'rx')
hold on
fplot(@(x) a*x.^2+b*x+c) %<---------- fplot is more convenient here
hold off
else
disp ('no real roots') %<---------- missing quote
[x1,x2]=deal([]) %<---------- missing default assignment
end
end
  2 Comments
Grady
Grady on 12 Jul 2024
This code will not work for me I am using 2024a.
Steven Lord
Steven Lord on 13 Jul 2024
What does "will not work" mean in this context?
  • Do you receive warning and/or error messages? If so the full and exact text of those messages (all the text displayed in orange and/or red in the Command Window) may be useful in determining what's going on and how to avoid the warning and/or error.
  • Does it do something different than what you expected? If so, what did it do and what did you expect it to do?
  • Did MATLAB crash? If so please send the crash log file (with a description of what you were running or doing in MATLAB when the crash occured) to Technical Support so we can investigate.
Show us how you tried to use this code as well.

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