Decision Branching Error in matlab onramp

How to crack this error? The input data and solution provided by the matlab sources are same still the error is occuring.

[Sneham Shrikant Vaidya]

if doPlot
plot(density)
title("Sample Densities")
xticklabels(element)
ylabel("Density (g/cm^3)")
else 
    disp("The density of" + element + " is  " + density)
end

// Just paste the following code or simply remove dashed line infront of solution in else statement

[Heena Singh]

i have tried this too, but still its not working!

[shubham kumar]

how to do

[Walter Roberson]

    disp("The density of " + element + " is  " + density)

Notice the space needed after "of"

[Venkateshan Shanmugam]

I tried using the same . But still the same error

[Venkateshan Shanmugam]

I got the solution just Enclose

if (doplot == 1)

[Mahmoud]

still have the same problem

[prashant]

When doPlot is 0, did you not plot the data?

[prashant]

Modify the script so that the plotting code on lines 5–8 execute only if doPlot is 1

Answer 1

[Steven Lord]

That might be checking that the densities that are printed as text when doPlot is 0 exactly match the densities that would be printed by "the code as shown above". The code you're using doesn't exactly match: note that your code doesn't display a space between "of" and the name of the element. Try adding the spacing before and after the element name (as I believe "the code as shown above" does) and see if that allows you to pass the test case.

[N/A]

yes, got the solution. Thank you.

[Damilola Adeniji]

Hello Girish

Please share the solution for this code.

As i'm currently stuck at this stage.

Thanks

[Steven Lord]

Compare:

x = 1;
y = 2;
disp("The value of x is" + x + "and the value of y is" + y)
disp("The value of x is " + x + " and the value of y is " + y)

The two phrases displayed are not identical. If your code displayed the first of those phrases but the exercise expected the second your code would not pass the test.

[Damilola Adeniji]

Hi Steve

Thanks for the quick response.

Even after following the phrase is still saying incorrect.

thanks.

Answer 2

[Ivan Derkunskii]

You'll be laughing, but you need just put spaces inside the phrases "The density of the" and "is" so that they look like "The density of the " (a space after the whole phrase) and " is " (spaces before and after the word).

[Abdul Rehman]

Yes! it really worked.

[Saurabh Shah]

Why is it so that after giving sapce it cosidered the code valid ?

[Steven Lord]

Adding or removing spaces can change the meaning of a word or phrase.

"I'm Popeye The Sailor Man" is somewhat different from "I'm Popeye The Sail or Man". In the former, Popeye is a man who sails. In the latter, Popeye could be a man or could be part of a ship.

If you were asked to name the theme song for the cartoon character, the former would be marked correct but the latter would not.

[Rasim Tawfeeq]

I've also tried this, but it still does not work!

There is no skipping at this point!

[shubham kumar]

how to crack this tried a lot

[Rupesh Shrestha]

HAHAHAHAHA Exactly!!!!

I tried putting spaces too but I had missed one space. Then again I tried with spaces in all places, it finally works.

if doPlot
    plot(density)
    title("Sample Densities")
    xticklabels(element)
    ylabel("Density (g/cm^3)")
else
    disp(" The density of " + element ...
        + " is " + density)
end

[Rahul Das A H]

load datafile
density = data(:,1);
if doPlot == 1
    plot(density)
    title("Sample Densities")
    xticklabels(element)
    ylabel("Density (g/cm^3)")
end

[Walter Roberson]

Comparing to 1 is not necessary in the case where the values are guaranteed to be either 0 or 1.

In the case where the values are not guaranteed to be one of those two, then you need to know whether the rule is that the number must be exactly 1 to pass, or if the rule is that the number must not be zero to pass.

Answer 3

[Bongani Tavengwa]

if doPlot
    plot(density)
    title("Sample Densities")
    xticklabels(element)
    ylabel("Density (g/cm^3)")
else 
    disp("The density of" + element + "is" + density)
end

[Bongani Tavengwa]

where did i go wrong ?????

[Bongani Tavengwa]

please do stage by stage when giving answer

[Steven Lord]

name = "Bongani Tavengwa";
disp("Do you see the problem now" + name)
disp("Do you see the problem now " + name)

Do you see the difference in the two displayed statements? What's the difference between the second and third lines of code and what impact does that difference have in the displayed text?

Answer 4

[Sreekanth K M]

if doPlot
   plot(density)
   title("Sample Densities")
   xticklabels(element)
   ylabel("Density (g/cm^3)")
else
   disp(" The density of " + element + " is " + density)
end 

[Milagros Walker]

still stuck in here

[Steven Lord]

Without seeing what you tried we can't determine why what you tried isn't working.

[Venkateshan Shanmugam]

I tried all the Solutions still the same error

[KRISTINA PAMELA RAMOS]

delete/remove lines 5-8

start with if doPlot == 1 and so on

it will work

[Ashutosh Pal]

It worked. Thanks

[Wurood]

@ KRISTINA PAMELA RAMOS Thank you so much , finally it works

Answer 5

[Surya Karthik Nadupalle]

The problem is solved only when you give gaps between words in the bracket. Notice the spacing i gave. It worked

disp(" The density of " + element + " is " + density)

[Milagros Walker]

still di not work

[Venkateshan Shanmugam]

Still Did not work

[Walter Roberson]

@Venkateshan Shanmugam

We do not know what code you are using.

I also have not seen a copy of the question being asked.

Answer 6

[1805645]

Hey, I have the same problem. How should I fix it?

[Attilio Pallage Don]

just clear the default code in task 1&2, then try the code......!!!!!!

[Walter Roberson]

You have plot(density) left over from Task 1 & 2. You are required to modify the code so that that plot() does not occur if doPlot is not 1.

[Racha]

Hi, I have also the same problem! What should I do ??

[DGM]

If you have the same problem, then Walter already gave the answer. If you have a different problem, nobody can possibly know what it is unless you describe it.