ode45 solve and taking current state as input
Show older comments
Hi
Can anyone help me how to fix this problem?
my questions are blow:
this is my function to be solved:
function dx = CSmacro_derive(x,fluid_params,dQ,dV,h_in,dm_in,dm_out)
dx=zeros(3,1);
v=x(1)/x(2);
h=fluid_params.h;
P=fluid_params.P;
dx(1)=dV;
dx(2)=dm_in-dm_out;
dx(3)=(1/(x(2)*fluid_params.dudT))*...
(dQ+((h_in-h)*dm_in)+(P+fluid_params.dudv)*(v*dx(2)-dx(1)));
end
This my main script:
t=linspace(0,10,10);
dV =0.1*sin(t);
dm_in=0.5;
dm_out=0;
% Initial condition
V=0.3326;
m=1;
T=15 + Kel;
x0=[V;m;T];
% Upstream refrigerant
v_in = 0.3326;
T_in = 15 + Kel;
fluid_in = refprop(v_in,T_in,r410a);
h_in=fluid_in.h;
[~,~,dQ] = convecCool(theta_a,x(3),convec_params);
fluid_params = CSmacro_props(x,r410a);
%this is my question.
%how can I take the current x value as my input to these two functions.
for i=length(t)
dx = @(t,x) CSmacro_derive(x,fluid_params,dQ,dV(i),h_in,dm_in,dm_out);
opts=odeset('RelTol',1e-6);
[t,x] = ode45(dx,t,x0,opts);
end
Thanks!
6 Comments
Torsten
on 24 Apr 2019
By calling "convecCool" and "CSmacro_props" from "CSmacro_derive"
WANYI ZHANG
on 24 Apr 2019
Put the lines marked in bold after the line
function dx = CSmacro_derive(x,fluid_params,dQ,dV,h_in,dm_in,dm_out)
and remove fluid_params,dQ from the list of passed parameters (because they are recalculated now in "CSmacro_derive" for the actual x-vector):
function dx = CSmacro_derive(x,dV,h_in,dm_in,dm_out)
WANYI ZHANG
on 24 Apr 2019
Torsten
on 24 Apr 2019
You changed
dx = @(t,x) CSmacro_derive(x,fluid_params,dQ,dV(i),h_in,dm_in,dm_out);
to
dx = @(t,x) CSmacro_derive(x,dV(i),h_in,dm_in,dm_out);
?
Jan
on 24 Apr 2019
I've formatted the code as code to improve the readability. Please do this by your own in future posts. Thank you.
Answers (0)
Categories
Find more on Programming in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!