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Could anyone help me to solve the issue.

Asked by jaah navi on 18 Apr 2019
Latest activity Edited by Torsten
on 18 Apr 2019
I am having 5 users whose initial_position are generated by the code itself and gives the value as follows:
All the 5 values are generated inside for loop in my code by running the loop 5 times.
Once the initial position is generated i need to find one common_position which is the maximum initial_position .
So i used the command ,common_position=max(initial_position) outside the for loop in order to find it
I got the result as common_position=2.5384e+06.
In the next step i need to use the expression of (common_position-initial_position)
so far in my code common_position is one which is calculated outside for loop, but initial_position is five which gets calculated inside for loop
Could anyone help me how can i use the expression of (common_position-initial_position) to generate 5 different values with respect to the difference of two positions.


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1 Answer

Answer by Torsten
on 18 Apr 2019
Edited by Torsten
on 18 Apr 2019

If "initial_position" is an array with 5 elements and "common_position" is a scalar, you can simply type
difference = common_position-initial_position


"initial_position" is an array with 5 elements generated inside the for loop
"common_position" is also an array with 1 element generated outside the for loop
If i use the command
difference = common_position-initial_position
outside the for loop it generates only one value.
but it need to be done with respect to 5 elements.
Could you please help me on this.
on 18 Apr 2019
No, it will generate 5 values (if "initial_position" really is an array with 5 elements, as you claim).

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