Can't understand why does it say "The expression to the left of the equals sign is not a valid target for an assignment."
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1-  function dydt = lagrang(~, y)
2-  syms m1 m2 m3 l1 l2 l3 g
3-  dydt = zeros(6,5,4,3,2,1);
4-  m1=1; m2=1; m3=1; l1=1; l2=1; l3=1; g=9.81;
5-  dydt(1)=y(2);
6-  dydt(3)=y(4);
7-  dydt(5)=y(6);
8-  dydt(1)*(l1^2*(m1+m2+m3))+dydt(3)((m2+m3)*l1*l2*cos(y(1)-y(3)))+dydt(5)*(m3*l1*l3*cos(y(1)-y(5)))=-(m2+m3)*l1*l2*y(4)^2*sin(y(1)-y(3))-m3*l1*l3*y(6)^2*sin(y(1)-y(5))-(m1+m2+m3)*g*l1*cos(y(1));
9-  dydt(1)*((m2+m3)*l1*l2*cos((y(1)-y(3))))+dydt(3)*(l2^2*(m2+m3))+dydt(5)*(m3*l2*l3*cos(y(3)-y(5)))=(m2+m3)*l1*l2*y(2)^2*sin(y(1)-y(3))-m3*l2*l3*y(6)^2*sin(y(3)-y(5))-(m2+m3)*g*l2*cos(y(3));
10- dydt(1)*(m3*l1*l3*cos(y(1)-y(5)))+dydt(2)*m3*l2*l3*cos(y(3)-y(5))+dydt(l3^2*m3)=m3*l1*l3*y(2)^2*sin(y(1)-y(5))+m3*l2*l3*y(4)^2*sin(y(3)-y(5))-m3*g**l3*cos(y(5))
%other part
dydt = [0; pi/2; 0; pi/2; 0; pi/2];
[t1,y1] = ode45(@lagrang, [0 20], dydt);
plot(t1,y1(:,2));
When I run this, I get a problem. Sorry if this is a simple problem to solve, since I am new to this program, it's been one week for me since i started.
Error: File: lagrang.m Line: 8 Column: 98
The expression to the left of the equals sign is not a valid target for an assignment.
Error in odearguments (line 90)
f0 = feval(ode,t0,y0,args{:});   % ODE15I sets args{1} to yp0.
Error in ode45 (line 115)
    odearguments(FcnHandlesUsed, solver_name, ode, tspan, y0, options, varargin);
Error in lagrange_ans (line 2)
[t1,y1] = ode45(@lagrang, [0 20], dydt);
The equations' itself:
 
 
Where do i go wrong?
Accepted Answer
  madhan ravi
      
      
 on 2 Jan 2019
        syms theta1(t) theta2(t) theta3(t)
 m1=1; m2=1; m3=1; l1=1; l2=1;
 l3=1; g=9.81; tau1=1; tau2=1; tau3=1;
e1= diff(theta1,2)*(l1^2*(m1+m2+m3)+l1)+...
    diff(theta1,2)*((m2+m3)*(l1*l2*cos(theta1-theta2)))+...
    diff(theta3,2)*(m3*l1*l3*cos(theta1-theta3))==...
    -(m2+m3)*(l1*l2*diff(theta2)^2*sin(theta1-theta2))-...
    m3*l1*l3*diff(theta3)^2*sin(theta1-theta3)-...
    (m1+m2+m3)*g*l1*cos(theta1)+tau1-tau2;
e2= diff(theta1,2)*((m2+m3)*l1*l2*cos(theta1-theta2))+...
    diff(theta2,2)*(l2^2*(m2+m3)+l2)+...
    diff(theta3,2)*(m3*l2*l3*cos(theta2-theta3))==...
    (m2+m3)*l1*l2*diff(theta1)^2*sin(theta1-theta2)-...
    m3*l2*l3*diff(theta3)^2*sin(theta2-theta3)-...
    (m2+m3)*g*l2*cos(theta2)+tau2-tau3;
e3= diff(theta1,2)*(m3*l1*l3*cos(theta1-theta3))+...
    diff(theta2,2)*(m3*l2*l3*cos(theta2-theta3))+...
    diff(theta3,2)*(l3^2*m3+l3)==...
    m3*l1*l3*diff(theta1)^2*sin(theta1-theta3)+...
    m3*l2*l3*diff(theta2)^2*sin(theta2-theta3)-...
    m3*g*l3*cos(theta3)+tau3;
vars = [theta1(t); theta2(t); theta3(t)]
V = odeToVectorField([e1,e2,e3])
M = matlabFunction(V,'vars', {'t','Y'})
interval = [0 20];  %time interval
y0 = [0; pi/2; 0; pi/2; 0; pi/2];   %initial conditions
ySol = ode45(M,interval,y0);
tValues = linspace(interval(1),interval(2),1000);
for i = 1:6 % denotes the number of solutions
yValues = deval(ySol,tValues,i); % i denotes the solution number
plot(tValues,yValues)
hold on
end
Plot of 6 solutions:

5 Comments
More Answers (2)
  Steven Lord
    
      
 on 2 Jan 2019
        
      Edited: Steven Lord
    
      
 on 2 Jan 2019
  
      When you use the equals sign to perform assignment, the left-hand side must be a variable or a "piece" of a variable. The following work:
x = 42; % Assigning to a variable
y([2 3 5]) = [1 2 3] % Assigning to a "piece" of a variable
S.z(3) = -999 % Assigning to a piece of a field of a struct array
 Let's look at your line 8. I've broken it into pieces using ... so we can read it without wrapping.
dydt(1)*(l1^2*(m1+m2+m3)) ...
+dydt(3)((m2+m3)*l1*l2*cos(y(1)-y(3))) ...
+dydt(5)*(m3*l1*l3*cos(y(1)-y(5))) = ...
-(m2+m3)*l1*l2*y(4)^2*sin(y(1)-y(3)) ...
-m3*l1*l3*y(6)^2*sin(y(1)-y(5))...
-(m1+m2+m3)*g*l1*cos(y(1));
You're trying to assign the result of the computations on the right side of the equals sign to another expression. MATLAB doesn't know what you're trying to assign here. Are you trying to update dydt(1), dydt(3), and dydt(5)? Are you trying to update y(1), y(3), and y(5)?
Because MATLAB can't figure out what you're trying to do, it throws an error. You will need to rewrite your higher order ODE as a system of first-order ODEs as shown in the "Solve Nonstiff Equation" example on the documentation page for ode45. Depending on whether some of those values are constants you may want to use a mass matrix to make rewriting your system a bit easier. See the fem2ode and batonode example files that show how to use a mass matrix.
3 Comments
  Steven Lord
    
      
 on 2 Jan 2019
				Have you tried the MATLAB Onramp course on this page? That's designed to teach you the basics quickly and I believe it's only two or three hours long (with exercises and videos.)
  KSSV
      
      
 on 2 Jan 2019
        
      Edited: KSSV
      
      
 on 2 Jan 2019
  
      Don't use syms
function dydt = lagrang(~, y)
dydt = zeros(6,5,4,3,2,1);
m1=1; m2=1; m3=1; l1=1; l2=1; l3=1; g=9.81;
dydt(1)=y(2);
dydt(3)=y(4);
dydt(5)=y(6);
dydt(1)*(l1^2*(m1+m2+m3))+dydt(3)((m2+m3)*l1*l2*cos(y(1)-y(3)))+dydt(5)*(m3*l1*l3*cos(y(1)-y(5)))=-(m2+m3)*l1*l2*y(4)^2*sin(y(1)-y(3))-m3*l1*l3*y(6)^2*sin(y(1)-y(5))-(m1+m2+m3)*g*l1*cos(y(1));
dydt(1)*((m2+m3)*l1*l2*cos((y(1)-y(3))))+dydt(3)*(l2^2*(m2+m3))+dydt(5)*(m3*l2*l3*cos(y(3)-y(5)))=(m2+m3)*l1*l2*y(2)^2*sin(y(1)-y(3))-m3*l2*l3*y(6)^2*sin(y(3)-y(5))-(m2+m3)*g*l2*cos(y(3));
dydt(1)*(m3*l1*l3*cos(y(1)-y(5)))+dydt(2)*m3*l2*l3*cos(y(3)-y(5))+dydt(l3^2*m3)=m3*l1*l3*y(2)^2*sin(y(1)-y(5))+m3*l2*l3*y(4)^2*sin(y(3)-y(5))-m3*g**l3*cos(y(5))
%other part
dydt = [0; pi/2; 0; pi/2; 0; pi/2];
[t1,y1] = ode45(@lagrang, [0 20], dydt);
plot(t1,y1(:,2));
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