Solving differential equation with varying Constant
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Dimensions
 G= 1x100, H=1X100;
I want to solve these 7 eqns. I am using ODE45. I am able to solve these equations for fixed T and Q. But i want to solve it for varying T and Q. Thats why i am using for loop. Can some one explain where am I wrong?. I have tried myself but unable to figure it out. 
function [dUdt]=eqn(t,U)
 dUdt=zeros(7,1);
 K=0.003;
for i=1:100
    T=G(1,i);
    Q=H(1,i);
end
 dUdt(1)=2*K*T(i)*(U(2)-U(1));
 dUdt(2)=-2*K*U(2)*T(i);
 dUdt(3)=K*T(i)*(2*Q(i)-U(3))-U(3)*K*(U(1)+2*U(2));
 dUdt(4)=K*U(3)*T(i)-U(4)*K*(U(1)+2*U(2));
 dUdt(5)=K*Q(i)*(U(1)+2*U(2))-2*K*U(5)*T(i);
 dUdt(6)=K*U(3)*(U(1)+2*U(2))+2*K*U(5)*T(i)-K*U(6)*T(i);
 dUdt(7)=K*U(6)*T(i)+U(4)*K*(U(1)+2*U(2)); 
end
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Answers (1)
  Torsten
      
      
 on 20 Dec 2018
        function [dUdt]=eqn(t,U)
 dUdt=zeros(7,1);
 K=0.003;
 t_inter=0:99;
 T_actual=interp1(t_inter,G,t);
 Q_actual=interp1(t_inter,H,t);
 dUdt(1)=2*K*T_actual*(U(2)-U(1));
 dUdt(2)=-2*K*U(2)*T_actual;
 dUdt(3)=K*T_actual*(2*Q_actual-U(3))-U(3)*K*(U(1)+2*U(2));
 dUdt(4)=K*U(3)*T_actual-U(4)*K*(U(1)+2*U(2));
 dUdt(5)=K*Q_actual*(U(1)+2*U(2))-2*K*U(5)*T_actual;
 dUdt(6)=K*U(3)*(U(1)+2*U(2))+2*K*U(5)*T_actual-K*U(6)*T_actual;
 dUdt(7)=K*U(6)*T_actual+U(4)*K*(U(1)+2*U(2)); 
 end
8 Comments
  Torsten
      
      
 on 20 Dec 2018
				As a quick and dirty solution, add the line
global G H
in "eqn" as well as in the function of your program where you define G and H.
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