Extracting data from a 'for' loop
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I have the following input file 'Test_14-Dec-2018.xls' attached
This is my code:
clc;
clear;
dataset = xlsread('Test_14-Dec-2018');
A = dataset(:,1:8);
B = A(A(:,1)==10,:); %for a=10s
k=1;
C=cell(1,4);
for p = 1:4
j=p*9;
i=j-8;
C{k} = B(i:j,:);
d=cell2mat(C);
x = d(:,2);
k=k+1;
end
Basically what the code does is extract that data into the matlab workspace and selects the data only when the first column has '10' data.
In the for loop, every 9 rows are selected and assigned a cell so that I have 9x8 in each 4 cells.
Cell2mat converts those cells into one matrix of 9x32. I am able to extract the second column from that.
Now, I want the data from every 8th column i.e. d(:,8), d(:,16), d(:,24), d(:,32) in a for loop but I am unable to do that.
After that I should be able to plot 'x' with each of those data from each column.
Any kind of help will be appreciated.
10 Comments
Bob Thompson
on 17 Dec 2018
What do you mean by, "I am unable to do that?" Have you run into some kind of error? Do you not know the commands necessary? Or do you not know the exact formulation for such a task?
Yoham Parelkar
on 17 Dec 2018
Bob Thompson
on 17 Dec 2018
You're unable to save more than d(:,32) because you're overwriting y each time you run the loop. If you want to save each result from a loop you should index your result. A better way of doing this would be the following.
y = d(:,[8,16,24,32]);
Yoham Parelkar
on 17 Dec 2018
Bob Thompson
on 17 Dec 2018
Edited: Bob Thompson
on 18 Dec 2018
for i = 1:floor(size(d,2)/8);
y(:,i) = d(:,i*8);
end
Try that.
Yoham Parelkar
on 17 Dec 2018
Image Analyst
on 18 Dec 2018
Bob, again, please, answers down below in the answers section, not up here in the comments section.
Bob Thompson
on 18 Dec 2018
Ha, you are correct, I had an error. It has been fixed now.
Yoham Parelkar
on 18 Dec 2018
Bob Thompson
on 18 Dec 2018
You need to set 'hold on'. That will allow you to plot multiple lines on the same figure. You can do this before the loop.
Accepted Answer
More Answers (1)
madhan ravi
on 17 Dec 2018
Edited: madhan ravi
on 17 Dec 2018
Replying to your latter comment :
y=cell(1,numel(1:8:32));
for l=1:8:32
y{l}=d(:,l);
end
celldisp(y) % [y{:}] to convert it to double from cell
y=d(:,[1:8:32])
3 Comments
Yoham Parelkar
on 17 Dec 2018
madhan ravi
on 17 Dec 2018
Anytime :) , if my code worked make sure to accept the answer else let know what needs to be done after you analyse(take your time) let me take a short nap by then ;-).
Yoham Parelkar
on 18 Dec 2018
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