Function definition not supported in this context. Create functions in code file.
Show older comments
Below is my code to solve the parallel plate capacitor problem.
clear all
x=linspace(1,20,10);
y=linspace(1,20,10);
[X,Y]=meshgrid(x,y);
C=delaunay(X(:),Y(:));
xy=[X(:) Y(:)];
Np=length(xy);
S=MatGlob(xy,C);
F=sparse(Np,1);
V0=1;
G=1e12;
for k=1:Np;
if x(k)==1
S(k,k)=S(k,k)+G;
F(k)=G*(-V0);
if x(k)==20
S(k,k)=S(k,k)+G;
F(k)=G*(+V0);
end
V=S\F;
figure
plot(xy,V,'*-')
title('potential(V)')
xlabel('postition(m)')
ylabel('postition(m)')
hold on
function S=MatGlob(xy,C)
Np=length(xy);
S=sparse(Np,Np);
Epsr=3.5;
Ne=size(C,1);
for k=1:Ne
N=C(k,:);
x1=xy(N(1),1);
x2=xy(N(2),1);
x3=xy(N(3),1);
y1=xy(N(1),2);
y2=xy(N(2),2);
y3=xy(N(3),2);
abc1=[1 x1 y1;1 x2 y2;1 x3 y3]\[1;0;0];
abc2=[1 x1 y1;1 x2 y2;1 x3 y3]\[0;1;0];
abc3=[1 x1 y1;1 x2 y2;1 x3 y3]\[0;0;1];
Grad=[abc1(2) abc2(2) abc3(2); abc1(3) abc2(3) abc3(3)];
Se=Epsr*(Grad'*Grad)*abs((x2-x1)*(y3-y1)-(x3-x1)*(y2-y1))/2;
S(N,N)=S(N,N)+Se;
end
end
Yet, Matlab annouce the error as follows: "Function definition not supported in this context. Create functions in code file" Would you please help me to fix this error? Thank you in advance.
5 Comments
Adam
on 11 Oct 2018
What version of Matlab are you using?
Simplest option is to do exactly what the error suggests though - create a new .m file, put the function in there and add it to your path.
@Duc Tu Vu: your code is badly aligned. Badly aligned code is one way that beginners hide bugs in their code, just like you have done. You should align your code using the default MATLAB Editor settings. You can also align existing code: select the code and press ctrl+i.
Mebo Valle
on 8 Dec 2021
I am experiencing the same problem, i have tried to align but nothing is happening, its just a simple and small code
function myRand
a=1+rand(3,4)*9
end
using R2019a
Mebo Valle
on 8 Dec 2021

Adam
on 8 Dec 2021
And you are getting the error about function definitions not being permitted in that context or some other problem?
Accepted Answer
More Answers (1)
Duc Tu Vu
on 11 Oct 2018
0 votes
5 Comments
WHISKY Chen
on 23 Mar 2019
How did you solve that problem? Could you please help me!
I have the same problem and... haven't solved it.
egg
on 16 Jul 2019
same here!
Steven Lord
on 16 Jul 2019
Try smart indenting your code to determine if you're trying to define a nested function inside an if, for, while, etc. statement (which is not allowed.)
Also make sure you're using release R2016b or later. The ability to define functions in scripts was introduced in release R2016b and will not work in earlier releases.
Naireeta Deb
on 27 Feb 2020
It doesn't work :/
Steven Lord
on 27 Feb 2020
Without more information about what you're doing (and ideally a small example with which you can reproduce the error) it's unlikely we'll be able to give you a more specific suggestion than what I did in my comment immediately before yours.
Make sure you're using release R2016b or later and make sure you're not trying to define the function inside an if, for, while, etc. statement (and you're not trying to define it by typing "function myoutput = ..." at the prompt in the Command Window.)
Categories
Find more on Entering Commands in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!