how to get the all possible combination between two range of numbers

every time this code iterate random number between 1 to 4. for 1st iteration c=2 and g=2. for second iteration c=1 and g=2; i need never the combination repeated once it comes

xx=4 
c= randi(length(xx))
g= randi(length(xx))

[Stephen23]

xx=4 
c= randi(length(xx))
g= randi(length(xx))

xx is scalar, so length(xx) is 1, which means both randi calls will always produce the same output:

>> xx = 4;
>> randi(length(xx))
ans =  1
>> randi(length(xx))
ans =  1
>> randi(length(xx))
ans =  1
>> randi(length(xx))
ans =  1
>> randi(length(xx))
ans =  1
>> randi(length(xx))
ans =  1
>> randi(length(xx))
ans =  1
... etc

Is this the intended behavior?

[Sun Heat]

xx=1:4

Answer 1

[KL]

The example and description is a but confusing but if you ask how to get the all possible combination between two range of numbers, use perms

 my_range = 1:4; %or even [1 3 5]...
 c = perms(my_range)

[Sun Heat]

thanks for reply..........actually i have two variable 'c' and 'g' that value should not be matched and acquire all possible combination like (c=1 and g=1),(c=1 and g=2),(c=1 and g=3).....and so on upto all combination.

[KL]

Hmmm.. I'm still not very sure but is this what you want,

c = repmat(1:4,4,1);
g = repmat(1:4,1,4);
x = [c(:) g(:)]

[Sun Heat]

thanks.....this works....but i need to know is there any function in matlab to do so as our number of variable(c,g,etc) increases....

[Steven Lord]

How many variables are you planning to use and how many values will each variable be able to take on? If you want to solve with too many variables or with variables that can take on too many different values, you may need to consider a new approach for solving your problem that avoids combinatorial explosion.