Using fsolve - solve for multiple variables using one input
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I'm not new to Matlab, but I am quite bad at it. I need to run an optimization problem on the general shock wave equations and I am stuck. So, I have the 3 conservation equations (shown below as fmass, fmom, fen1, and fen2). fen2 is just another equation to solve for change in enthalpy. My problem is I have 4 unknowns: P2, rho2, u2, and DeltaH, but only one input (P). Here, P is an initial guess for P2. What I need is to give the function one input and have it solve for the 4 unknowns. It will do so when the DeltaH from fe1 = DeltaH from fen2. I hope this makes sense. The most important thing here is to find the proper DeltaH using ONLY my initial guess of P2. I'm not quite sure how to do this; like I said, I'm not very good at this. Here is the function code I have so far (I attached the file as well):
function F = deltah(P)
% The vector P is a vector of the unknowns in these equations, i.e. P2
rho1 = 2.3916; %kg/m3
P1 = 78600; %Pa
T1 = 295; %K
u1 = 372.3516; %m/s
kappa = 1.28641936633961e-05;
beta = 0.0034;
cp = 778.253929133643;
cv = 666.318314616417;
% fmass = conservation of mass equation
fmass = X(3) - (rho1*u1)/X(2);
% fmom = conservation of momentum equation
fmom = X(1) - P1 + (((rho1^2)*(u1^2))/X(2)) - rho1*(u1^2);
% fen1 = conservation of energy equation in terms of u and rho
fen1 = X(4) - (u1^2)/2 + (((rho1^2)*(u1^2))/(2*(X(2)^2)));
% fen2 = conservation of energy equation in terms of thermodynamic
% coefficients cp, cv, beta, the density rho, and pressure
fen2 = X(4) - (X(1)-P1)*(cv*kappa/beta) + (cp/beta)*(ln(X(2)/rho1));
F = [fmass; fmom; fen1; fen2];
end
Update: I thought this worked when I gave initial guesses for everything, but it doesn't. I'm really stuck now.
4 Comments
Torsten
on 21 Mar 2018
Edited: Torsten
on 21 Mar 2018
And what problems do you encounter if you add initial values for X0 and run the following code ?
X0 = ...;
[Soln] = fsolve(@deltah,X0,options)
function F = deltah(X)
% The vector P is a vector of the unknowns in these equations, i.e. P2
rho1 = 2.3916; %kg/m3
P1 = 78600; %Pa
T1 = 295; %K
u1 = 372.3516; %m/s
kappa = 1.28641936633961e-05;
beta = 0.0034;
cp = 778.253929133643;
cv = 666.318314616417;
% fmass = conservation of mass equation
fmass = X(3) - (rho1*u1)/X(2);
% fmom = conservation of momentum equation
fmom = X(1) - P1 + (((rho1^2)*(u1^2))/X(2)) - rho1*(u1^2);
% fen1 = conservation of energy equation in terms of u and rho
fen1 = X(4) - (u1^2)/2 + (((rho1^2)*(u1^2))/(2*(X(2)^2)));
% fen2 = conservation of energy equation in terms of thermodynamic
% coefficients cp, cv, beta, the density rho, and pressure
fen2 = X(4) - (X(1)-P1)*(cv*kappa/beta) + (cp/beta)*(ln(X(2)/rho1));
F = [fmass; fmom; fen1; fen2];
end
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