how to write a program to compute those
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1.Write a Matlab program to compute the following:
1.1) B=1+2+3+5+8+13+-------------(stop the program when B>100)
1.2) B=1/1! + 1/2! + 1/3! + 1/5! + 1/8! +----------(stop the program when B>1.67)
6 Comments
ANKUR KUMAR
on 29 Dec 2017
Come up with some trail codes. We will surely push you to get on the desired result.
Jan
on 29 Dec 2017
There is an infinite number of different sequences starting with: 1,2,3,5,8,13, ... As usual for homework questions: Please post, what you have tried so far and ask a specific question.
Image Analyst
on 29 Dec 2017
And for 1.2, C does not depend on, or change B, so it will never stop.
Roger Stafford
on 29 Dec 2017
Edited: Roger Stafford
on 29 Dec 2017
The person devising this homework almost certainly has the Fibonacci numbers in mind but starting with 1 and 2.
Image Analyst
on 29 Dec 2017
OK, I see you changed 1.2 to refer to B now instead of C so now it makes sense to say you want to "stop the program when B>1.67". So how far have you come using the hint I gave you below in the answers section? It should be trivial after that. That was 2 hours ago - you should be done by now.
Rena Berman
on 2 Jan 2018
(Answers Dev) Restored edit
Answers (2)
Image Analyst
on 29 Dec 2017
Edited: Image Analyst
on 2 Jan 2018
Regarding:
1.Write a Matlab program to compute the following:
1.1) B=1+2+3+5+8+13+-------------(stop the program when B>100)
1.2) B=1/1! + 1/2! + 1/3! + 1/5! + 1/8! +----------(stop the program when B>1.67)
Hint:
First make the series in an array vec = [1,2,3,4,.....]
vec = [1, 2]
for k = 3 : 10
vec(k) = vec(......
end
Then use cumsum() or a for loop to sum it up.
For 1.2 use factorial and the dot divide operator ./
2 Comments
Roger Stafford
on 29 Dec 2017
@Image Analyst: That's the wrong series! It should be the Fibonacci series except that it starts with 1 and 2. Try this for the second question:
F1 = 1; F2 = 2;
B = 1+1/2;
while true
T = F2+F1;
F1 = F2;
F2 = T;
B = B+1/factorial(F2);
if B > 1.67, break, end
end
Image Analyst
on 29 Dec 2017
Edited: Image Analyst
on 29 Dec 2017
I recognized that but when I was trying to generate the vector [1,2,3,5,8,13,...]
vec = [1, 2]
for k = 3 : 10
vec(k) = vec(k-1) + vec(k-2);
end
vec
We see
vec =
1 2 3 5 8 13 21 34 55 89
Which is exactly the vector I was going for. Now the student merely needs to sum up that vector in a for loop, a while loop, or by using cumsum() to get B.
Don't you agree that this is a reasonable first step? Maybe not the way someone else would approach it but it is one way.
And for the second step (generating factorial terms), don't you think this is a reasonable first step:
vec2 = 1 ./ factorial(vec)
vec2 =
Columns 1 through 8
1 0.5 0.16667 0.0083333 .....
Which is again summed using a for loop, a while loop, or cumsum() depending on how you want to do it. Anyway those were the approached I thought of and I think they will give the correct answer (with a little more code).
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