Variable appears to change size on every loop iteration

Hi to everybody i have a problem running these codes .its a linear segment price in power generation economic dispatch matlab code
in line 17 AND SOME OTHER LINES THIS ERROR COMES: Variable F appears to change size on every loop iteration I DONT KNOW HOW TO SOLVE THAT!

1 Comment

Note that this is a warning, not an error. It hints that your code is less efficient than it could be. For large arrays the cost of growing the array can end up being a major slowdown.

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Answers (2)

The solution is to pre-allocate:
Do
results = ones(1,10)
for ii = 1:10
results(ii) = ii;
end
instead of:
for ii = 1:10
begin_for_error(ii) = ii;
end
I didn't go through your code so you'll have to modify to fit your needs.

5 Comments

And replace
q=1;
for i=1:N % converts the column matrix "x" to a rectangular shape
% for easy row addition on next loop
for j=1:N
X(i,j)=x(q);
q=q+1;
end
end
by:
X = reshape(x, N, N);
Learn to use vectorized expressions. The fact that they are faster might not matter in your case, but they are cleaner and leaner: Less chances for typos and easier to write and maintain.
What if you don't want to allocate specific values to the enteries of the array? I got the same one while I was trying to plot an animation. Is there a way of optimising it as the exceution of my code is noticably slow.
Since the goal is to overwrite them anyway, does it matter what value it starts out with?
You could consider pre-allocating with NaN, as many functions will ignore those.
If you want more specific advice, you should post this as a separate question.

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function waterfallspect(s, fs, spectsize, spectnum)
%WATERFALLSPECT Display spectrum of signal s as a 3-D plot.
% s - input signal, use wavload to load a WAV file
% fs - Sampling frequency (Hz).
% spectsize - FFT window size
% spectnum - number of windows to analyze
frequencies = [0:fs/spectsize:fs/2];
offset = floor((length(s)-spectsize)/spectnum);
for i=0:(spectnum-1)
start = i*offset;
A = abs(fft(s((1+start):(start+spectsize))));
magnitude(:,(i+1)) = A(1:spectnum/2+1);
end
waterfall(frequencies, 0:(spectnum-1), magnitude');
xlabel('frequency');
ylabel('time');
zlabel('magnitude');

1 Comment

No, this would have the same warning as the original code, about a variable changing size in every iteration, so this code would not fix the problem that the original poster had.
Is there a reason you did not pre-allocate the matrix magnitude ?

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Asked:

on 2 Jan 2017

Edited:

on 17 Oct 2023

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