The memory use of a sparse matrix depends on its history

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The amount of memory used by a sparse matrix depends on its history. In a project this week, a matrix that could have consumed a few bytes was consuming gigabytes of memory.
Demonstration:
J = sparse(zeros(2,2));
J2 = [J zeros(2,2); zeros(1,4)];
J3 = sparse(zeros(3,4)); % same data as J2
isequal(J2,J3)
%ans =
% logical
% 1
whos('J2')
% Name Size Bytes Class Attributes
% J2 3x4 88 double sparse
whos('J3')
% Name Size Bytes Class Attributes
% J3 3x4 56 double sparse
%
% 88 > 56!

Accepted Answer

Steve Van Hooser
Steve Van Hooser on 26 Feb 2025

More Answers (1)

Steven Lord
Steven Lord on 26 Feb 2025
The amount of memory required by a sparse matrix is not just a function of the number of rows and columns but also the number of non-zero elements stored and the number of non-zero locations allocated for storage. In the case of your J2 and J3, they are the same size but have different numbers of locations allocated for storage.
J = sparse(zeros(2,2));
J2 = [J zeros(2,2); zeros(1,4)];
J3 = sparse(zeros(3,4)); % same data as J2
numberOfNonzerosInJ2 = nnz(J2)
numberOfNonzerosInJ2 = 0
numberOfNonzerosAllocatedInJ2 = nzmax(J2)
numberOfNonzerosAllocatedInJ2 = 3
numberOfNonzerosInJ3 = nnz(J3)
numberOfNonzerosInJ3 = 0
numberOfNonzerosAllocatedInJ3 = nzmax(J3)
numberOfNonzerosAllocatedInJ3 = 1
If you know how many non-zero elements you're ultimately going to want your sparse matrix to contain, use the spalloc function to preallocate it.
J4 = spalloc(height(J2), width(J2), 2); % Matrix is same size as J2, but only 2 nonzero locations
whos J*
Name Size Bytes Class Attributes J 2x2 40 double sparse J2 3x4 88 double sparse J3 3x4 56 double sparse J4 3x4 72 double sparse
  2 Comments
James Tursa
James Tursa on 26 Feb 2025
Edited: James Tursa on 26 Feb 2025
As a follow up, when encountered in operations MATLAB will shrink the resulting sparse memory allocation to the minimum size necessary. I am unaware of any published rules for what operations will trigger this, but it does seem to happen for the "usual" stuff. E.g.,
S = spalloc(1000,1000,10000);
T = S + sparse(0);
whos
Name Size Bytes Class Attributes S 1000x1000 168008 double sparse T 1000x1000 8024 double sparse

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