How can i rewrite this logic for n elements?

if q(1,1) == 1
disp("q1 is selected")
D = D1;
P= P1;
elseif q(1,2) == 1
disp("q2 is selected")
D = D2;
P= P2;
elseif q(1,3) == 1
disp("q3 is selected")
D = D3;
P= P3;
end
Hello I have to re-write this logic for 10elements i.e what if q array consists of 1*10 slots unlike above i have just 3. also it is very unpredictable that when the value of q elements can be 1.

4 Comments

Torsten
Torsten on 28 Feb 2023
Edited: Torsten on 28 Feb 2023
Exactly one of the q(1,:) equals 1 ? Or could there be several ? Or none ?
exactly one of the q values = 1.

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 Accepted Answer

Or...
Dvals = [D1, D2, D3, D4, D5, D6, D7, D8, D9, D10];
Pvals = [P1, P2, P3, P4, P5, P6, P7, P9, P9, P10];
idx = find(q == 1, 1); %first
if ~isempty(idx)
D = Dvals(idx);
P = Pvals(idx);
else
uh oh
end

3 Comments

The code seems right but doesnt work when D1,...D10 or P1,..P10 are arrays not single values.
@Sumanth So then learn to use arrays in their many forms, possibly multidimensional arrays, or cell arrays.
Dvals = {D1, D2, D3, D4, D5, D6, D7, D8, D9, D10};
Pvals = {P1, P2, P3, P4, P5, P6, P7, P9, P9, P10};
idx = find(q == 1, 1); %first
if ~isempty(idx)
D = Dvals{idx};
P = Pvals{idx};
else
uh oh
end

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