Hi! How can I create a conditional statement from checking if an array is empty? I will paste my non-working code here.

TF = isempty(matches); %true-false statement: logical 1 = True, logical 0 = False
GRRRRR = double(TF);

if GRRRRR == 1 %%if it is true that matches is empty
    fprintf['No match has been found throughout whole run'];

[SL: formatted code as code]

Answer 1

[Steven Lord]

You don't actually have to convert the logical value into double and compare it to 1. From the documentation for the if keyword: "if expression, statements, end evaluates an expression, and executes a group of statements when the expression is true." The only problems I see with your code is that you're not using parentheses to call fprintf and that you didn't end the if block with an end statement (though that latter problem could be that you just didn't copy and paste it from your code.)

x = [];
if isempty(x)
    fprintf('The x array is empty');
else
    fprintf('The x array is not empty');
end

The x array is empty

Answer 2

[Hanojhan Rajahrajasingh]

A = zeros(0,2,2);
TF = isempty(A);
GRRRRR = double(TF);
if GRRRRR == 1
    fprintf('No match has been found throughout whole run');
else
    fprintf('Match has been found');
end

No match has been found throughout whole run