Heat transient equation not executing

2 views (last 30 days)
Reji G
Reji G on 17 Sep 2022
Commented: Torsten on 17 Sep 2022
I want to implement this formula in matlab. But i couldn't. So it'd be great if anyone can help me. Where x&t ranges from 0.1 to 10.
  2 Comments
Torsten
Torsten on 17 Sep 2022
Please show us your attempt.
Reji G
Reji G on 17 Sep 2022
Moved: Star Strider on 17 Sep 2022
clc;
close all;
clear all;
T1=300;
Ti = 350;
L = 10;
alpha = 100;
syms n
T = symsum((exp(((-n*pi)/(2*L))*(alpha*t)))*sin((n*pi*x)/(2*L)),n,1,9)
T(x,t) = T1+((4/pi)*(Ti-T1)*T);

Sign in to comment.

Answers (1)

Torsten
Torsten on 17 Sep 2022
The terms in your series do not agree with the formula you posted.
You must decide which one is correct and which one is wrong.
clc;
close all;
clear all;
T1 = 300;
Ti = 350;
L = 10;
alpha = 100;
syms n t x
T = symsum((exp(((-n*pi)/(2*L))*(alpha*t)))*sin((n*pi*x)/(2*L)),n,1,20);
T = T1+4/pi*(Ti-T1)*T;
T = matlabFunction(T);
x = 0:0.1:L;
t = 0:0.1:1;
[X,TIME] = meshgrid(x,t);
surf(TIME,X,T(TIME,X))
  2 Comments
Reji G
Reji G on 17 Sep 2022
I need Temperature value(T(x,t)). an x y plot is required. Not the graph you plotted
Torsten
Torsten on 17 Sep 2022
clc;
close all;
clear all;
T1 = 300;
Ti = 350;
L = 10;
alpha = 100;
syms n t x
T = symsum((exp(((-n*pi)/(2*L))*(alpha*t)))*sin((n*pi*x)/(2*L)),n,1,20);
T = T1+4/pi*(Ti-T1)*T;
T = matlabFunction(T);
x = 0:0.01:L;
t = 0.1;
figure(1)
plot(x,T(t,x))
x = L/2;
t = 0:0.001:0.5;
figure(2)
plot(t,T(t,x))

Sign in to comment.

Products


Release

R2019b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!