# How do i delete the spaces that are in the middle of a string array?

7 views (last 30 days)
Sameer Raza on 25 Jul 2022
Answered: Githin George on 26 Jul 2022
str=' 123 456 ';
strtrim(str)
strfind('123 456',' ')
so far i know that using strtrim will remove the leading and trailing blanks in the string vector but how do i remove the space that is between 123 and 456? i can use strfind to help me know which element of the string vector is a blank space but how would i be able to delete the elements themselves?

the cyclist on 25 Jul 2022
Here is one way:
str=' 123 456 ';
str(str==' ') = []
str = '123456'
This method relies on the fact that the white space is a space character (and not some of the other whitespace characters).

Voss on 25 Jul 2022
To delete elements from an array, set them to [] (or '').
% to removes spaces (' '):
str=' 123 456 ';
str(str == ' ') = []
str = '123456'
% this also works:
str=' 123 456 ';
str(str == ' ') = ''
str = '123456'
% to remove any whitespace:
str=' 123 456 ';
str(isstrprop(str,'wspace')) = []
str = '123456'

Paul on 26 Jul 2022
replace seems to do the trick
Single char:
str=' 123 456 ';
replace(str,whitespacePattern,'')
ans = '123456'
Cell array of chars
replace({str;str},whitespacePattern,'')
ans = 2×1 cell array
{'123456'} {'123456'}
String array
str1 = string(str)
str1 = " 123 456 "
replace([str1;str1],whitespacePattern,'')
ans = 2×1 string array
"123456" "123456"

Githin George on 26 Jul 2022
Hi Sameer,
My understanding is that you would like to remove any and all multiple spaces from your string to single space and trim the start and end. You could to use the following code to get it done.
mystr = ' Some string one ';
% \s+ means multiple spaces
mystr = regexprep(mystr,'\s+',' ');
strtrim(mystr)
ans = 'Some string one'
I hope it helps!

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