How to find vector with if loops and for loops

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Given a vector u with the dimension 20x1, which consists of random variables from a uniform distribution (distributed on [0,1]) exists. Instructions: • Create a code in MATLAB, – which creates the vector u, – which contains both ’for loops’ and ’if loops’, – and for all values in the vector u indicates in which quarter the number lies.This is one of my mathlab final exam question, could you please help me,i just know that i should use "rand" function
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Accepted Answer

Image Analyst
Image Analyst on 16 Jun 2022
Are you allowed to turn in other people's solutions as your own for your final exam question?
The first 5 values of the 20-element u lie in the first quarter, the next 5 in the second quarter, the third 5 in the third quarter, and the final 5 elements in indexes 16-20 obviously lie in the last quarter. But I think they want you to use a for loop
u = rand( % You said you got this
for k = 1 : length(u)
if u(k)...........
More code
end
end
You can either store the quarter that the number lives in, in a vector called quarter, or maybe you just want to print out the quarter it's in using fprintf(). Or maybe you want to do both.
  15 Comments
Torsten
Torsten on 24 Jun 2022
Edited: Torsten on 24 Jun 2022
I like if the order of the conditions in if-statements can be changed.
This is not the case in this simplified version because
if r(k) < 0.75
quarter(k) = 3;
elseif r(k) < 0.25
quarter(k) = 1;
elseif r(k) < 0.5
quarter(k) = 2;
else
quarter(k) = 4;
end
would create chaos.

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