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余弦累加函数作图问题。
a=-pi/4:pi/999:pi/4; n=2:2:1000; for ii = 1:length(a) y1(ii)=0.3/sum((cos(n.*(pi/9))./((n.^2-1).^2))).*sum(cos(n.*(pi/9)).*co...
2 years ago | 0
| accepted
