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Question
求非线性方程的数值解。
现有方程 f = @(x) ((r^2/cos((r-x)/r)-(r-x)*sqrt(2*r*x-x^2))*L-V)，其中r=2,L=5,V=8,要求f=0的根。这是一个实际问题，所以0<x<2*r 我使用过二分法、正割法、牛顿-拉普森方法，还有fz...
3 years ago | 1 answer | 0
