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matlab 非线性方程组求解。
a=[0.5 0.5 0.5]; i1=@(y1)8*(1-(0.2194+0.02).*(y1+a(3)-0.02)/3)*2727.98; i2=@(y2)8*(1-(0.2194+0.02).*(y2+a(3)-0.02)/3)*2814.58;...
3 years ago | 0
| accepted
