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使用最小二乘法求桥梁桩身受力，结果系数飚到11次方了，求教一下是什么问题
%此函数用于计算火车经过时桥梁沿桩身不同位置的受力曲线 %使用方法为最小二乘法 %Aa+Bb=D %Ba+Cb=E %所有输出结果均保留三位有效数字 %图像显示至第100次，即66.7s处 function regression() N=...
3 years ago | 1 answer | 0
