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Last seen: ongeveer 2 jaar ago Active since 2022

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step and impulse response of a system
i have a question which is the following: impulse respone of a system is h(t) =( exp(-0.05*t) ) Excitation of a system is x(t...

ongeveer 2 jaar ago | 1 answer | 0

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calculating conditional probability in Matlab
Q: Rust Rider cars are produced in four factories. The first factory produces 380 cars per day, the second 260, the third 150...

ongeveer 2 jaar ago | 1 answer | 0

1

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calculating probability in Matlab
i have this question: create a MATLAB function that approximates the probability in the following experiment with simulations!T...

ongeveer 2 jaar ago | 1 answer | 0

1

answer

Question


finding probability in Matlab
i have a question which it is the following: Create a MATLAB function that approximates the probability in the following exper...

ongeveer 2 jaar ago | 1 answer | 0

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partial sum of a series
i have this function and i wrote the following code to calculate the Fourier coefficients im just stuck with writing a...

meer dan 2 jaar ago | 1 answer | 0

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Question


odd and even functions
given this function is there a way in matlab with which i can know is its odd, even or neither?

meer dan 2 jaar ago | 2 answers | 0

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answers

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Fourier coefficients of a function
given this function with this interval is there any way to calculate the Fourier coefficients (ak, a0, bk) of this fuction i...

meer dan 2 jaar ago | 2 answers | 0

2

answers

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problem regarding plotting cuvres
I am supposed to plot 3 curves on the same figure, The first plot is ok( the red one ), but the other 2 I am getting 2 separat...

meer dan 2 jaar ago | 1 answer | 0

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Solving Differential Equations Symbolically and Numerically
given this equation end two initial values, how can i solve it symbolically, i know how to solve the first one but im stuck...

meer dan 2 jaar ago | 1 answer | 0

1

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Question


question related to direction field
equation: x*y'+y-(1+x)*exp(x)=0 domain [-2, 1] [-2, 2] initial values y(-1)=-1 y(-1)=1 y(1/2)=1 code: syms y(x); e...

meer dan 2 jaar ago | 1 answer | 0

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