charles alexander
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Provide your first answer ever to someone else's question
Awarded to charles alexander on 21 Nov 2020
Answer 1 question that was unanswered for more than 30 days
Awarded to charles alexander on 21 Nov 2020
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variance-covariance matrix EWMA
it is simple, the matrix is distributive. a(bk)=ab(K). the variable k is 14. i suggest this matrix; {a1n a2n a10} by ...
meer dan 3 jaar ago | 0
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