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lsqnonlinで同じ評価関数・変数・入力に対して，普通に使用した場合と分割して使用した場合とで結果が違うのは何故なのでしょうか．
lsqnonlinにおいて，評価関数として次の関数 fuction values = funcOpt(num,r,X,Y) values = []; for i=1:1:num Y_ = Y(3*i-2+3*i,:); % 3*1ベクトル ...
6 years ago | 1 answer | 0
