Let's assume that we have a pair of two gears(pinion-bigger gear). The goal is to calculate the gear ratio(i) given the number (z) of the teeth on both gears. The number of teeth on pinion will be zp and the number of teeth on the bigger gear will be zg. Also assume that the starting gear is the pinion.
Tips:
1)BE CAREFULL OF THE REAL WORLD LOGIC!!! (The output can also be:'Not a gear' or 'Not a pair of pinion and gear').
2)The only unreasonable thing is that one gear can have almost infinite teeth.
3) If you find the logic of tip 1, the messages should be in order. First you shoul write about the 'Not a gear' message and then about the 'Not a pair of pinion and gear message.
GOOD LUCK!!!!!!!!!!!!!!!!!
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