Could you be more specific on the underlying relationship between the input (timetable) and output (mean duration)? That is, among which group are you calculating the mean duration? From your example, there are only 2 groups of destinations, i.e., BOS and NYC, but why there are 3 values in the output? What's the mapping behind? Also, your problems including Part 1, 4, 5 are all based on single test, which allows hard-coded solution to lead.
Peng do share the grouping method cause it eludes me :)
There seems to be an error with the test suite: the first mean time should be 03:09:50 and not 03:09:05. And the test code should probably be abs(ttDur - Dur) <= duration([0 0 1]) (not 0.01).
This is not a solution. It returns just a single value instead of 3 and somehow works.
Eventually figured out the grouping method in this problem, which is not so obvious...
This is a proper solution and with small size.
Read a column of numbers and interpolate missing data
Back to basics 7 - Equal NaNs
Spot the outlier
Try 1.5.4: Celsius to Fahrenheit
Find the index of the largest value in any vector X=[4,3,4,5,9,12,0,4.....5]
Use a timetable to analyze a train timetable (Part 2)
Use a timetable to analyze a train timetable (Part 1)
Use a timetable to analyze a train timetable (Part 3)
Use a timetable to analyze a train timetable (Part 5)
Find the treasures in MATLAB Central and discover how the community can help you!
Choose a web site to get translated content where available and see local events and offers. Based on your location, we recommend that you select: .
You can also select a web site from the following list:
Select the China site (in Chinese or English) for best site performance. Other MathWorks country sites are not optimized for visits from your location.
Contact your local office